问题
Consider the following jmh benchmark
@State(Scope.Benchmark)
@BenchmarkMode(Array(Mode.Throughput))
class So59893913 {
def seq(xs: Seq[Int]) = xs.sum
def range(xs: Range) = xs.sum
val xs = 1 until 100000000
@Benchmark def _seq = seq(xs)
@Benchmark def _range = range(xs)
}
Given xs references the same object of runtime class Range.Inclusive passed in as argument to seq and range methods, hence dynamic dispatch should invoke the same implementation of sum, despite differing declared static type of method parameter, why the performance seems to differ so drastically as indicated below?
sbt "jmh:run -i 10 -wi 5 -f 2 -t 1 -prof gc bench.So59893913"
[info] Benchmark Mode Cnt Score Error Units
[info] So59893913._range thrpt 20 334923591.408 ± 22126865.963 ops/s
[info] So59893913._range:·gc.alloc.rate thrpt 20 ≈ 10⁻⁴ MB/sec
[info] So59893913._range:·gc.alloc.rate.norm thrpt 20 ≈ 10⁻⁷ B/op
[info] So59893913._range:·gc.count thrpt 20 ≈ 0 counts
[info] So59893913._seq thrpt 20 193509091.399 ± 2347303.746 ops/s
[info] So59893913._seq:·gc.alloc.rate thrpt 20 2811.311 ± 34.142 MB/sec
[info] So59893913._seq:·gc.alloc.rate.norm thrpt 20 16.000 ± 0.001 B/op
[info] So59893913._seq:·gc.churn.PS_Eden_Space thrpt 20 2811.954 ± 33.656 MB/sec
[info] So59893913._seq:·gc.churn.PS_Eden_Space.norm thrpt 20 16.004 ± 0.035 B/op
[info] So59893913._seq:·gc.churn.PS_Survivor_Space thrpt 20 0.013 ± 0.005 MB/sec
[info] So59893913._seq:·gc.churn.PS_Survivor_Space.norm thrpt 20 ≈ 10⁻⁴ B/op
[info] So59893913._seq:·gc.count thrpt 20 3729.000 counts
[info] So59893913._seq:·gc.time thrpt 20 1864.000 ms
Particularly notice the difference in gc.alloc.rate metrics.
回答1:
Two things are going on.
The first is that when xs has the static type Range then that call to sum is a monomorphic method call (because sum is final in Range) and the JVM can easily inline that method and optimize it further. When xs has the static type Seq then it becomes a megamorphic method call which won't get inlined and fully optimized.
The second is that the methods that get called are not actually the same. The compiler generates two sum methods in Range:
scala> :javap -p scala.collection.immutable.Range
Compiled from "Range.scala"
public abstract class scala.collection.immutable.Range extends scala.collection.immutable.AbstractSeq<java.lang.Object> implements scala.collection.immutable.IndexedSeq<java.lang.Object>, scala.collection.immutable.StrictOptimizedSeqOps<java.lang.Object, scala.collection.immutable.IndexedSeq, scala.collection.immutable.IndexedSeq<java.lang.Object>>, java.io.Serializable {
...
public final <B> int sum(scala.math.Numeric<B>);
...
public final java.lang.Object sum(scala.math.Numeric);
...
}
The first one contains the actual implementation that you see in the source code. And as you can see it returns an unboxed int. The second one is this:
public final java.lang.Object sum(scala.math.Numeric);
Code:
0: aload_0
1: aload_1
2: invokevirtual #898 // Method sum:(Lscala/math/Numeric;)I
5: invokestatic #893 // Method scala/runtime/BoxesRunTime.boxToInteger:(I)Ljava/lang/Integer;
8: areturn
As you see this one just calls the other sum method and boxes the int into a java.lang.Integer.
So in your method seq the compiler only knows about the existence of the sum method that has return type java.lang.Object and calls that one. It probably doesn't get inlined and the java.lang.Integer that it returns has to be unboxed again so seq can return an int. In range the compiler can generate a call to the "real" sum method without having to box and unbox the results. The JVM can also do a better job at inlining and optimizing the code.
来源:https://stackoverflow.com/questions/59899811/different-performance-of-object-with-same-runtime-class-but-different-static-typ