JQuery-csv not parsing all values

问题

I am using jquery.csv to parse a csv file and show the data in a table format.

my csv file data: test.csv

header1, header2, header3, header4
value1, value2, value3, value4
value1, value2, value3, value4.1,value4.2,value4.3
value1, value2, value3, value4

My code: index.html

    var data;

    $.ajax({

        type: "GET",

        url: "test.csv",

        dataType: "text",

        success: function(response) {

            data = $.csv.toObjects(reponse);

            // generating the table for user view
            generateTable(data);

        var html = generateTable(data);

        $('#result').html(html);

    }

});

function generateTable(data) {

    var html = '';

    if (typeof(data[0]) === 'undefined') {

        return null;

    }

    if (data[0].constructor === Object) {

        for (var row in data) {

            html += '<tr>\r\n';

            for (var item in data[row]) {

                html += '<td>' + item + ':' + data[row][item] + '</td>\r\n';

            }

            html += '</tr>\r\n';

        }

    }

    return html;

}

The code doesnt generate an error and it shows in the table that i print is one value per header, but I would want to know how can I get several value per header? Like for header4 there are several values and I would want all values in the cell for header4. Or if you can suggest any better way of parsing this kind of data I would appreciate it. thanx!

JSFiddle

http://jsfiddle.net/xpvt214o/685678/

回答1:

So... Now I understood your question, hehe. Here we go:

            function generateTable(lines) {
                if (typeof(lines) === 'undefined' || lines.length == 0) {
                    return '';
                }
                var header = lines[0].split(',');
                var html = '';
                for (var row in lines) {
                    if(row == 0) {
                        continue;
                    }
                    html += '<tr>\r\n';
                    var cols = lines[row].split(',');
                    for (var col in cols) {
                        var item = header[col] ? header[col] : header[header.length-1];
                        html += '<td>' + item + ':' + cols[col] + '</td>\r\n';
                    }
                    html += '</tr>\r\n';
                }
                return html;
            }
            $.ajax({
                type: "GET",
                url: "test.csv",
                dataType: "text",
                success: function(response) {
                    $('#result').html(generateTable($.csv.parsers.splitLines(response)));
                }
            });

You can't do what you want just using the default parser. So you should create your own parser with $.csv.parsers.splitLines helper (you can read about that there). So you can do whatever you want to do with those values of overflow cases. In your case, you want to use the last "column header" as the header of those values, right? That's happening on this line:

var item = header[col] ? header[col] : header[header.length-1];

If that column exists on the header definition, it'll call the header name. If doesn't, it'll call the last header name. That's it?

回答2:

I checked your fiddle and made a console.log to let me print out your parsed csv object. It prints the variable without the last two items from line 3. Your problem is that the csv parser dropps these items. I think this happens due to your incorect csv.

You should add your csv like this to make it parsed correclty:

header1, header2, header3, header4,header4.2,header4.3
value1, value2, value3, value4,,
value1, value2, value3, value4.1,value4.2,value4.3
value1, value2, value3, value4,,

I think the csv-parser needs an equal amount of elements on each row.

I've tested this csv in your fiddle and it shows all elements, but add empty or undefined ones for 2nd and 4th row.

来源：https://stackoverflow.com/questions/52038618/jquery-csv-not-parsing-all-values

标签

jquery

html

jquery-csv