non-copying istringstream

丶灬走出姿态 提交于 2020-01-23 04:46:11

问题


So istringstream copies the contents of a string when initialised, e.g

string moo("one two three four");
istringstream iss(moo.c_str());

I was wondering if there's a way to make std::istringstream use the given c_str as its buffer without copying things. This way, it won't have to copy large bits of memory before passing the std::istringstream& to functions that take istream& as an argument.

What I've been trying to do is convert some functions which only take std::ifstream& arguments (they're mostly parsers) into taking istream& as well. Would I have to make my own istream subclass for this?


回答1:


It's fairly trivial to write a basic std::streambuf class that reads from a given memory area. You can then construct an istream from this and read from that.

initializing a C++ std::istringstream from an in memory buffer?

Note that the lifetime of the buffer pointed to be c_str() is very limited, though, and there's no guarantee that a call to c_str() want cause some copying although I don't know of any implementations where it does.




回答2:


Using istringstream is not a satisfactory solution, because this copies the entire buffer.

A previous answer suggests the deprecated istrstream, but as this generates warnings and may be removed in future, a better solution is to use boost::iostreams:

boost::iostreams::stream<boost::iostreams::array_source> stream(moo.c_str(), moo.size());

This avoids copying the buffer in the same way istrstream did, and saves you having to write your own stream class.




回答3:


the deprecated istrstream supports this feature.

#include <string>
#include <strstream>
using namespace std;

int main(int argc, char* argv[])
{
    string moo = "one two three four";
    istrstream istr(const_cast<char*>(moo.c_str()),moo.size());
    std::string line;
    while(!istr.fail() && !istr.eof()){
        getline(istr,line,' ');
        cout << line << "_";
    }
    // prints: one_two_three_four_
}



回答4:


There's only a copy because the parameter you pass, a const char*, requires conversion to the argument type of the istringstream constructor.

Just pass in the string without calling c_str().

istringstream iss(moo);

Well ok, that doesn't prevent copying completely, but it eliminates an unnecessary copy. To completely eliminate the copy, you'd have to rewrite std::stringbuf, which specifically avoids working directly on the string you give it.




回答5:


It depends on what a std::string does. According to 27.2.1/1 The class basic_istringstream<charT,traits,Allocator> ... uses a basic_stringbuf<charT,traits,Allocator> object to control the associated storage. Since the class must use an object it must copy construct the string into that object.

So the real question is not whether a stringstream copies the contents, but whether copy constructing a string will copy the contents or implement some sort of copy-on-write scheme.



来源:https://stackoverflow.com/questions/3122901/non-copying-istringstream

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