问题
I have no trouble making jsonp requests, however I'm unsure about setting up a web service to deliver responses in jsonp.
First, does a server need to be configured in a certain way to allow jsonp requests, or does the page just have to have the response properly formatted?
In my testing I have the following jsonp response from geonames.org (I've placed it a blank page on server/domain 1 with nothing else):
<?php echo $_GET['callback'];?>({"postalcodes":[{"adminName2":"Westchester","adminCode2":"119","postalcode":"10504","adminCode1":"NY","countryCode":"US","lng":-73.700942,"placeName":"Armonk","lat":41.136002,"adminName1":"New York"}]});
On server/domain 2 I'm making the following request:
$.ajax({
// works when I make the call to geonames.org instead of domain1
//url: 'http://www.geonames.org/postalCodeLookupJSON?postalcode=10504&country=US&callback=?',,
url: 'http://www.domain1.com/test/jsonp.php?callback=?',
success: function(data) {
$('#test').html(data);
},
});
The call works when I place the files on the same server (either domain 1 or 2) and turn it into a regular json request. What am I doing wrong?
Just to clarify: My question pertains to the page RECEIVING the request. I know the request works when I make it to geonames.org, flickr, etc... apis. However, I'm trying to set up a page to send a response. In my example I just have a blank page with hard coded jsonp. I'm not sure if I have to have some other headers on the page or have something enabled on my server.
回答1:
The response is wrong.
If you have the following url: http://www.mydomain.com/test/jsonp.php&callback=? jQuery will replace the question mark at the end of the url with a unique string. On the serverside you have to take this string($_GET['callback']) and use it as function-name in your response:
PHP-example:
<?php
$object=array('postalcodes'
=>array(
array(
"adminName2" => "Westchester",
"adminCode2" => "119",
"postalcode" => "10504",
"adminCode1" => "NY",
"countryCode" => "US",
"lng" => -73.700942,
"placeName" => "Armonk",
"lat" => 41.136002,
"adminName1" => "New York"
)));
echo $_GET['callback'].'('.json_encode($object).')';
?>
What happens with the response when receiving it? jQuery knows the unique string(assuming fx123456).
jQuery will create a <script>
-element with the src: http://www.mydomain.com/test/jsonp.php&callback=fx123456 . jQuery will call a on the fly created function named fx123456() . This function will return the JSON(as a object) which will be taken as data-argument of the success-function of $.ajax().
So if you don't use the callback-parameter provided by jQuery as functions-name inside the response, jQuery doesn't know the name of function to call(I better say jQuery will call a function that doesn't exist).
回答2:
I've always used $.getJSON() in place $.ajax for cross-browser requests so I don't know the specifics on calling json using $.ajax as you have here, but have you tried setting the dataType to jsonp?
Also, have you tried ?callback=? instead of &callback=?
$.ajax({
url: 'http://www.mydomain.com/test/jsonp.php?callback=?',
dataType: 'jsonp',
success: function(data) {
$('#test').html(data);
},
});
Lastly, when I run your test json into jsonlint.com it is not returning valid. It says syntax error, unexpected TINVALID at line 1 Parsing failed
来源:https://stackoverflow.com/questions/4373419/testing-a-static-jsonp-response