问题
Just about everyone reading this is probably familiar with these three key facts about C:
- When you mention the name of an array in an expression, it evaluates (most of the time) to a pointer to the array's first element.
- The "array subscripting" operator
[]works just as well for pointers as it does for arrays. - A function parameter that seems to be an array actually declares a pointer.
These three facts are absolutely central to array and pointer handling in C. They're not even three separate facts; they're interlinked facets of one central concept. It is not possible to do even fairly basic C programming properly without a decent understanding of this concept.
My question today is simply, What is the name for this concept?
I supposed I'm old-fashioned, but I've always called it "The equivalence between arrays and pointers in C", or "array/pointer equivalence" for short. But I've learned that you almost can't say those words on SO; they're pretty much taboo.
This may seem like an abstract or philosophical question, so to frame it more concretely, what I'm looking for is is a simple noun or noun phrase I could use in the sentence "Yes, due to _____, array subscripting can be thought of as syntactic sugar for pointer arithmetic", in answer to, say, this question.
(But please note that I am not looking for answers to that question, or for answers to the question "What's wrong with the word 'equivalence'?". Yes, I know, it can mislead learners into imagining that arrays and pointers are somehow the same. I did have that confusion in mind when I wrote this FAQ list entry.)
回答1:
- The "array subscripting" operator [] works just as well for pointers as it does for arrays.
No, in fact it only works for pointers. Whenever you type [] in an expression, you always get a pointer to the first element. This is guaranteed to happen since arr[i] must be equivalent to *(arr + i). The former is "syntactic sugar" for the latter.
- A function parameter that seems to be an array actually declares a pointer.
This is actually a special case, referred to as "array adjustment", where the compiler implicitly changes the declaration of a function parameter of array type into a pointer to the first element. The rationale is surely to make functions compatible with the "array decay" of expressions, but the C standard keeps the terms separate.
Both cases, expressions and function parameters, are often referred to informally as "array decay". Though sometimes this is only used for expressions and not for function parameters. I don't think there exists a single, consistent use of the term. "Array decay" is the best one I think, although the C standard does not use that term anywhere.
(I dislike the term "equivalence", because an array can turn into a pointer, but not the other way around. Indeed there's always countless beginners coming up with confused beliefs such as "arrays and pointers are the same thing". Calling them "equivalent" doesn't exactly help.)
回答2:
The C standard doesn't have a single word for this. It uses the word "conversion" when defining behavior (1) in 6.3.2.1p3, "equivalent" when defining behavior (2) in 6.5.2.1p2, and "adjustment" when defining behavior (3) in 6.7.6.3p7.
I am old-fashioned, and don't think there's anything wrong with calling this "array/pointer equivalence", provided it is clear in context that you are talking about expressions where (1) happens or function declarations where (3) happens. However, a more palatable term for the people who don't like "equivalence" would perhaps be "array-to-pointer conversion", since this confuses people most often when it's (1), I think.
回答3:
I would go with the term of array decay. This term goes well with what it suggests. The C standard doesn't say about it in this context and yes the first day I heard the term I went for searching it in the standard but I couldn't find it (So it's a bit confusing regarding who coined the term etc). Also alternatively one can write due to "most scenarios array is converted into pointer"... - No this is not a single Noun. But this is not letting any misinterpretation to take place. Standard itself says it the "conversion".
Most of the time I try to say it the long way and then put the word ("array decaying") in bracket. In fact there are answers where I didn't even mention it and just went with the standard's words of conversion into pointer.
回答4:
I suggest "array-to-pointer decay" is a reasonable shorthand, since "decay" is commonplace jargon in referring to the type conversion, with precedent elsewhere in the C FAQ: Question 6.12:
Q: Since array references decay into pointers, if arr is an array, what's the difference between arr and &arr?
An extended technical meaning of "decay" that includes this one has been adopted into C++ Standard Library nomenclature since C++11: std::decay
回答5:
There is no single name given to the three concepts mentioned, but I think describing them as implying any sort of "equivalence" is counter-productive, at least when describing "modern" C. While the results of array decay generally behave like pointers, C99 specifies that the pointers yielded by array decay are not required to be behave in the same way as pointers achieved via other means. Given:
char fetch_byte_at(void *p, int x) { return ((char*)p)[x]; }
struct {char arr[5][7];} s;
char test1(int x) { return s.arr[0][x]; }
char test2(int x) { return fetch_byte_at(&s, x); }
the Standard doesn't directly specify any reason why pointer value s.arr[0] used in test1 should not be equivalent to the pointer value ((char*)(void*)s) used when fetch_byte_at is called from test2. It does, however, simultaneously imply that test2 should be able to read out all the bytes of s [implying that it should work predictably with values of x up to at least 34] while saying that s.arr[0][x] is only meaningful for values of x up to 6.
While nothing in the Standard would contradict either of your first two points individually, it's not possible for both to hold. Either the result of an array decay is something other than an "ordinary" pointer to the array's first element, or applying the [] operator to an array has different semantics from applying it to a pointer. While it's unclear which of #1 and #2 has been invalidated by C99, they no longer together form any kind of "equivalence" in modern C.
If you recognize a distinction between traditional C and "modern" C, it might be useful to establish terms for the things that make the former useful. Such things go beyond the points you mention, however. Unfortunately, I don't know of any standard terms for such things, and would not look for the Standard to supply such terminology when it no longer supports the concepts involved.
回答6:
Thanks, everybody. I'm using this "answer" to summarize the answers people gave and my assessment of them, not as a proper answer I expect anyone to upvote or anything.
A lot of people put serious thought into this question, and I appreciate that. But at this point the only thing I can conclude is that there is no answer, today at least, to the question I had in mind.
Quite a few people suggested "array decay", and that's a very nice shot, but it doesn't work for me. It refers mostly to fact 1 and maybe fact 3 as listed in the original question, but not really fact 2. You can't say "Yes, due to array decay, array subscripting can be thought of as syntactic sugar for pointer arithmetic." (Or at least, you can't say that if your intent is to be clear and instructive.) You'd have to say something like "Yes, due to array decay and the way pointer arithmetic is defined so as to be consistent with it, array subscripting can be thought of as syntactic sugar for pointer arithmetic", which is, well, a different kettle of fish entirely.
Although I didn't say so explicitly, I was looking for a term in common, widespread, accepted use, although there was no requirement that it involve words actually used in the Standard. And given that no one coughed up such a term, given that everyone engaged in a certain amount of speculation and "What about ...?", I conclude that there is no single term in widespread use for the concept behind the trio of related facts. (Other than "equivalence", which is ruled out.)
A number of answerers and commentators said this (that there is no one answer) in various ways. I'm going to go ahead and accept Lundin's answer on that basis, and because others seem to have liked it the best.
Me, going forward I might try using "The correspondence between arrays and pointers in C" and see if it catches on. Arrays and pointers are as different as men and women, and they're actually pretty far apart, but they do exchange letters frequently. :-)
回答7:
This is a subtle question. Upon browsing an English thesaurus and dictionary, I came to find that the term similitude might be appropriate for your context.
By Oxford's Online Dictionary definition, the word Similar is defined as:
having a resemblance in appearance, character, or quantity, without being identical.
and the word Similitude as:
the quality or state of being similar to something.
Since arrays and pointers are not identical, but are sometimes treated similarly, we might say:
Yes, due to Array/Pointer similitude, array subscripting can be thought of as syntactic sugar for pointer arithmetic"
回答8:
This may seem like an abstract or philosophical question, so to frame it more concretely, what I'm looking for is is a simple noun or noun phrase I could use the sentence "Yes, due to _____, array subscription can be thought of as syntactic sugar for pointer arithmetic", in answer to, say, this question.
The Phrase you are looking for is "Yes, due to array subscribing being pointer arithmetic under the hood, array subscribing can be thought of as syntactic sugar for pointer arithmetic."
Which is of course, silly, because the reason for saying that array subscribing is syntactic sugar for pointer arithmetic is because that is exactly what it is, it does not require further explanation unless the person you are saying this to either does not know what 'array subscribing', 'pointer arithmetics' or 'syntactic sugar' mean. This is not to say the compiler does not know the difference of the two (it does because it is the one who is responsible for all the syntactic sugar you're getting as a result of that).
This same question could be raised about everything that any language does for us which we could do ourselves by using a higher number of lower level instructions and as such being able to refer to it using multiple terms that only change the amount of syntactic sugar used. The whole point is not to pretend like they are different (they always are in way, but that's not the point), but to make programming easier (just think about writing code without having the [] operator as syntactic sugar for pointer arithmetics, and you quickly realize the reason for its existence - it's not because it's different, it's because it's easier to write, read and manage).
(But please note that I am not looking for answers to that question, or for answers to the question "What's wrong with the word 'equivalence'?". Yes, I know, it can mislead learners into imagining that arrays and pointers are somehow the same. I did have that in mind when I wrote this FAQ list entry.)
Your question seems to be "What's a modern term for array pointer equivalence in the sense that array subscription is just syntactic sugar for pointer arithmetics?"
The answer is:
- "Array subscription" when you are using the [] operator to index an array.
- "Pointer arithmetics" when you are manually moving a pointer around (as opposed to using the [] operator). You might also feel like using this term for whatever math you are doing to the value you feed to the [] operator, but you are not really doing pointer arithmetics there, but rather "calculating an index", which is the term for the syntactic sugar of having the size of the objects in memory taken into account automatically for you (which again, is not different, just easier to write, read and manage, thus: syntactic sugar).
回答9:
Standard uses the term converted to. Array and pointer equivalence still holds better over array decay to pointers. Standard mention this term no where but it's just a mutual understanding between programmers that when it comes in the context of arrays and pointers it is thought as array and pointer equivalence. And what pointer and array equivalence means is: pointer arithmetic and array indexing [that] are equivalent in C, pointers and arrays are different..
回答10:
I agree that terms like "pointer/array equivalence" or "array decay" (into a pointer) are inaccurate and can be very misleading.
I'd propose the following:
Access into an array using the [] operator with an index has an equivalent pointer arithmetic expression. However, there is no equivalence between a pointer and an array: I can happily change a pointer's value (content), maybe to save a separate iteration counter, but I cannot do that with the "decayed" array; it is immutable, and in some respects, exhibits similar behaviour to C++ references.
Both verbs "to decay" and "to convert" in English invariably convey that the original is changed in the process. Using an array's name or using the unary '&' operator don't change their operand.
Therefore, an expression like "yields a pointer" or "creates a pointer" would be more accurate That is reflected in the fact that in both cases the resulting pointer is a temporary thing, (usually) sitting in a GP-register of the CPU, and cannot be assigned to.
At least that is my understanding, looking at disassemblies seems to confirm that.
回答11:
If you are referring to a type conversion, why not use the term 'casting'? It already is commonly understood to imply that the compiler is being coerced into treating two related but not-the-same types as if they were a desired type. Yes, there is an equivalence here but 'casting' is used as a way to indicate that the types aren't literally the same but that the compiler should treat a type as a different type and that the procedure is acceptable to the compiler, like up-casting for byte->long
2nd choice: "Synonym"
来源：https://stackoverflow.com/questions/48868367/whats-a-modern-term-for-array-pointer-equivalence