How to build a Jenkins job from pipeline ignoring if the job doesn't exist?

问题

I'm trying to build a job from my Jenkins pipeline like this:

 build job:"${jobName}", propagate:false, wait:false

Here ${jobName} is a multi branch pipeline job and as such may sometimes not exist in my workflow.

This step marks my build as failed if the job doesn't exist. Is there a way to simply ignore and move on if the job doesn't exist?

I tried to check whether the given job exist or not like this:

    if(jenkins.model.Jenkins.instance.getItem("${jobName}") != null) {
        println("Preparing to build the ${jobName}...")
        build job:"${jobName}", propagate:false, wait:false
    } else {
        println("Not building the job ${jobName} as it doesn't exist")
    }

However, this at times fails (due to script security?). Is there a better way of doing this? All I need is to build a job only if it exists.

回答1:

If you use a scripted pipeline, you can add a try-catch block:

try {
    println("Preparing to build the ${jobName}...")
    build job:"${jobName}", propagate:false, wait:false
} catch (NullPointerException e) {
    println("Not building the job ${jobName} as it doesn't exist")
}

来源：https://stackoverflow.com/questions/52054417/how-to-build-a-jenkins-job-from-pipeline-ignoring-if-the-job-doesnt-exist