问题
I have a list of divs with images in them:
<div class="wizard-img"><%= image_tag("sources/pix/nyt.png") %></div>
<div class="wizard-img"><%= image_tag("sources/pix/theguardian.png") %></div>
When a user clicks the div, I'd like it to change the image to x-on.png, when clicked again, it'll change to x-off.png, and when clicked a third time it should revert to x.png.
Is it possible to do this without manually specifying jQuery for every image change? Can I traverse the div and find the image name, and simply append the -off/-on to the image?
Thanks!
回答1:
Perhaps CSS sprites would work for you?
That would save you from loading a separate image every time you click the image (button?), and you could solve your problem by adding and removing a css-class, e.g.:
$('.wizard-img').click(
function() {
if ($(this).hasClass('on')) {
$(this).removeClass('on').addClass('off');
} else if ($(this).hasClass('off')) {
$(this).removeClass('off');
} else {
$(this).addClass('on');
}
}
);
回答2:
http://docs.jquery.com/Events/toggle
$(".wizard-img").toggle(
function () {
$(this).find("img").attr({src:"x-on.png"});
},
function () {
$(this).find("img").attr({src:"x-off.png"});
},
function () {
$(this).find("img").attr({src:"x.png"});
}
);
回答3:
CSS Sprites would indeed be the way to do this, but just for completeness, here's another option.
Normally I'm the last to reach for a regexp, but I think they'll help here
$('.wizard-img').click(function() {
var $img = $(this).find('img') ,
src = $img.attr('src') ,
onCheck = /\-on\.jpg$/ ,
offCheck = /\-off\.jpg$/ ,
normal = /\.jpg$/
;
if(src.match(onCheck)) {
$img.attr('src', src.replace(onCheck, '-off.jpg'));
} else if (src.match(offCheck)) {
$img.attr('src', src.replace(offCheck, '.jpg'));
} else {
$img.attr('src', src.replace(normal, '-on.jpg'));
}
});
回答4:
FWIW, I suggest you do this using plain CSS and background-image
. It sounds to me that this is not really normal images, but rather "buttons".
回答5:
I have found this plugin useful to do something similar to what you asked:
http://www.malsup.com/jquery/cycle/
回答6:
$('.wizard-img').click(function() {
var img = $(this).find('img');
var src = img.attr('src');
//image is neither on nor off, so change src to on and return
if(src != 'x-on.png' && src != 'x-off.png') {
img.attr('src','x-on.png');
return false;
}
//image is on, so change src to off and return
if(src == 'x-on.png') {
img.attr('src','x-off.png');
return false;
}
//image is off, so change src to x and return
if(src == 'x-off.png') {
img.attr('src','x.png');
return false;
}
});
回答7:
$("img").hover(
function() { this.src = this.src.replace("_Off", "_On");},
function() { this.src = this.src.replace("_On", "_Off");
});
http://kaidez.com/tutorial-simple-effective-jquery-image-rollover/
回答8:
I created plugin swapimg: http://xuannd.wordpress.com/2010/12/03/jquery-swap-images-easy/
use: $('.swapimg').swapimg();
opt: $('.swapimg').swapimg({imgOn:"_on.png", imgOff:".png"});
(function($){
$.fn.swapimg=function(options){
var defaults={imgOn:"_on.gif",imgOff:".gif"};
var options=$.extend(defaults,options);
var $isOn=false;
var $obj_index=-1;
return this.each(
function(){
if($(this).is('img')){
obj=$(this)
}
else{
obj=$(this).find('img')
}
obj.hover(
function(){
if(this.src.indexOf('_on')==-1){
$isOn=false
}else{
$isOn=true
}
if($isOn==false){
this.src=this.src.replace(options.imgOff,options.imgOn)
}
},
function(){
if($isOn==false){
this.src=this.src.replace(options.imgOn,options.imgOff)
}
}
)
}
)
}
})(jQuery);
来源:https://stackoverflow.com/questions/1062731/jquery-toggle-to-change-image