Is the code I'm using to make .zip files correct?

梦想的初衷 提交于 2020-01-06 03:42:21

问题


I'm using this code in C# to zip files.. I need to open these files in an Android app (java):

String mp3Files = "E:\\"; 
int TrimLength = mp3Files.ToString().Length;

byte[] obuffer;
string outPath = mp3Files + "\\" + i + ".zip";
ZipOutputStream oZipStream = new ZipOutputStream(File.Create(outPath)); // create zip stream
oZipStream.SetLevel(9); // maximum compression

foreach (string Fil in ar) // for each file, generate a zipentry
{

    oZipEntry = new ZipEntry(Fil.Remove(0, TrimLength));
    oZipStream.PutNextEntry(oZipEntry);

    if (!Fil.EndsWith(@"/")) // if a file ends with '/' its a directory
    {
        ostream = File.OpenRead(Fil);
        obuffer = new byte[ostream.Length];
        ostream.Read(obuffer, 0, obuffer.Length);
        oZipStream.Write(obuffer, 0, obuffer.Length);
    }
}
oZipStream.Finish();
oZipStream.Close();

I'm having problems in extracting these files in java and I want to make sure the problem isnt from zip files files.. so is this code correct? Can java read these zips?

I just tried to create normally using winrar and the file extraction code gives the same problem.. the problem is that "zin.getNextEntry()" is always null:

    String zipFile = Path + FileName;


            FileInputStream fin = new FileInputStream(zipFile);
            ZipInputStream zin = new ZipInputStream(fin);

            ZipEntry ze = null;
            while ((ze = zin.getNextEntry()) != null) {
                UnzipCounter++;
                if (ze.isDirectory()) {
                    dirChecker(ze.getName());
                } else {
                    FileOutputStream fout = new FileOutputStream(Path
                            + ze.getName());
                    while ((Unziplength = zin.read(Unzipbuffer)) > 0) {
                        fout.write(Unzipbuffer, 0, Unziplength);                    
                    }
                    zin.closeEntry();
                    fout.close();

                }

            }
            zin.close();

回答1:


Your problem might be due to FileInputStream object's mode. This link (has C# code) states the stream must be readable. Try changing your code according to their recommendation. Posting part of the code from their site:

using (var raw = File.Open(inputFileName, FileMode.Open, FileAccess.Read))
{
    using (var input= new ZipInputStream(raw))
    {
        ZipEntry e;
        while (( e = input.GetNextEntry()) != null)
        {



回答2:


From the dicussion we've had on this question, the size of your entry is being set to 4294967295, which is the reason you're having a problem with the unzip in java. Try setting the Size:

FileInfo fi = new FileInfo(Fil); // added this line here
oZipEntry = new ZipEntry(Fil.Remove(0, TrimLength));
oZipEntry.Size = fi.Length;              // added this line here
oZipStream.PutNextEntry(oZipEntry);

Apologies if the syntax is incorrect, this is untested.



来源:https://stackoverflow.com/questions/7587207/is-the-code-im-using-to-make-zip-files-correct

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