Pass value of a include to a variable

问题

Is it possible to pass the result of an include to a variable?

Let's consider this simple file 'example.html':

<p>some HTML</p>

In a PHP file, how can we pass the content of this file to a variable? I tried:

$my_variable = include('example.html');

It includes the file, but the value of $my_variable is 1.

回答1:

If you just want to get the content of file you can use this :

$data = file_get_contents("example.html");
echo htmlentities($data);

or this :

ob_start();
readfile("example.html");
$data = ob_get_clean();
echo htmlentities($data);

回答2:

use

ob_start();
include('example.html');
$output = ob_get_clean();// this will buffer your output

来源：https://stackoverflow.com/questions/29543504/pass-value-of-a-include-to-a-variable