Making a matrix of a specific structure

问题

Please note: I don't know where I am mistaking but I have spent whole day trying to solve this problem. So, I request not to discard it as duplicate question and treat this as a very specific question related to matrix structure.

I have the following data.frame:

dput(c.m.q)

structure(list(ASK_Price = c(1801, 1687.3, 1687.2, 1688.95, 1687.15, 
1688.95, 1687.5, 1688.85, 1689, 1688.95, 1687.5, 1688, 1688, 
1687.5, 1689.95, 1685.85, 1689.9, 1689.95, 1688.8, 1688.95, 1687.15, 
1687.2, 1690, 1688, 1688, 1690, 1688.7, 1690, 1688.7, 1689.9, 
1688.7, 1689.9, 1688.7, 1689.9, 1689.8, 1687.95, 1689.75, 1689.7, 
1687.95, 1689.35, 1689.3), BID_Price = c(1651, 1688.5, 1687, 
1688.5, 1687, 1688.5, 1687.05, 1688.5, 1687.05, 1687.05, 1688.5, 
1688.5, 1688.5, 1688.5, 1688.7, 1685.35, 1688.2, 1688.95, 1685.6, 
1685.6, 1689.05, 1685.8, 1689.1, 1686.1, 1686.25, 1689.95, 1688.05, 
1689.95, 1688.1, 1689.8, 1688.1, 1689.8, 1686.1, 1689.8, 1689.7, 
1686.15, 1689.7, 1689.15, 1686.15, 1689.15, 1689.15)), .Names = c("ASK_Price", 
"BID_Price"), row.names = c(1L, 17704L, 17707L, 17708L, 17709L, 
17710L, 17713L, 17714L, 17717L, 17720L, 17729L, 17732L, 17735L, 
17738L, 17983L, 17984L, 17985L, 17986L, 18015L, 18018L, 18029L, 
18032L, 18033L, 18223L, 18225L, 18226L, 18227L, 18228L, 18229L, 
18230L, 18231L, 18232L, 18233L, 18234L, 18235L, 18236L, 18237L, 
18238L, 18239L, 18240L, 18241L), class = "data.frame")

I want it to look similar to this in structure:

dput(mydata)

structure(c(4.56, 4.57, 4.53, 4.59, 4.55, 4.59, 4.59, 4.55, 4.55, 
4.55, 4.59, 4.55, 4.59, 4.59, 4.7, 4.64, 4.65, 4.66, 4.65, 4.66, 
4.66, 4.65, 4.65, 4.65, 4.66, 4.65, 4.66, 4.66), .Dim = c(14L, 2L))

I have tried the following:

c.m.q<-as.matrix(sapply(c.m.q, as.numeric))

But I don't get the similar matrix strucutre:

structure(c(1801, 1687.3, 1687.2, 1688.95, 1687.15, 1688.95, 
1687.5, 1688.85, 1689, 1688.95, 1687.5, 1688, 1688, 1687.5, 1689.95, 
1685.85, 1689.9, 1689.95, 1688.8, 1688.95, 1687.15, 1687.2, 1690, 
1688, 1688, 1690, 1688.7, 1690, 1688.7, 1689.9, 1688.7, 1689.9, 
1688.7, 1689.9, 1689.8, 1687.95, 1689.75, 1689.7, 1687.95, 1689.35, 
1689.3, 1651, 1688.5, 1687, 1688.5, 1687, 1688.5, 1687.05, 1688.5, 
1687.05, 1687.05, 1688.5, 1688.5, 1688.5, 1688.5, 1688.7, 1685.35, 
1688.2, 1688.95, 1685.6, 1685.6, 1689.05, 1685.8, 1689.1, 1686.1, 
1686.25, 1689.95, 1688.05, 1689.95, 1688.1, 1689.8, 1688.1, 1689.8, 
1686.1, 1689.8, 1689.7, 1686.15, 1689.7, 1689.15, 1686.15, 1689.15, 
1689.15), .Dim = c(41L, 2L), .Dimnames = list(NULL, c("ASK_Price", "BID_Price")))

回答1:

We can set the dimnames to NULL after converting to matrix (assuming from the expected output showed in the OP's post without any dimnames)

m1 <- `dimnames<-`(as.matrix(c.m.q), NULL)

If we check the dput of 'm1', it is of similar structure

dput(m1)

structure(c(1801, 1687.3, 1687.2, 1688.95, 1687.15, 1688.95, 
1687.5, 1688.85, 1689, 1688.95, 1687.5, 1688, 1688, 1687.5, 1689.95, 
1685.85, 1689.9, 1689.95, 1688.8, 1688.95, 1687.15, 1687.2, 1690, 
1688, 1688, 1690, 1688.7, 1690, 1688.7, 1689.9, 1688.7, 1689.9, 
1688.7, 1689.9, 1689.8, 1687.95, 1689.75, 1689.7, 1687.95, 1689.35, 
1689.3, 1651, 1688.5, 1687, 1688.5, 1687, 1688.5, 1687.05, 1688.5, 
1687.05, 1687.05, 1688.5, 1688.5, 1688.5, 1688.5, 1688.7, 1685.35, 
1688.2, 1688.95, 1685.6, 1685.6, 1689.05, 1685.8, 1689.1, 1686.1, 
1686.25, 1689.95, 1688.05, 1689.95, 1688.1, 1689.8, 1688.1, 1689.8, 
1686.1, 1689.8, 1689.7, 1686.15, 1689.7, 1689.15, 1686.15, 1689.15, 
1689.15), .Dim = c(41L, 2L))

来源：https://stackoverflow.com/questions/39064869/making-a-matrix-of-a-specific-structure

标签

matrix

dataframe