jQuery keyup function doesnt work?

时光毁灭记忆、已成空白 提交于 2019-12-30 08:57:10

问题


My HTML file:

<html>
<head>
  <script type="text/javascript" src="js/jquery-1.10.2.min.js"></script>
  <script type="text/javascript" src="js/scripts.js"></script>
  <link rel="stylesheet" type="text/css" href="style.css" />
  <title>
    Login
  </title>
</head>
<body>
<div class=loginForm>
  <p>Worker-ID:<input type=text id=workerID name=workerID /></p>
  <p>Password:<input type=password  id=workerPassword name=workerPassword /></p>
  <input type=submit id=submitLogin name=submitLogin value="Log in"/>
</div>
</body>
</html>

My scripts.js:

$('#workerID').keyup(function() {
    alert('key up');
);

It doesn't work at all. I tried everything space,one letter, numbers. The alert doesn't show up. Where is the mistake?


回答1:


Apart from a typo around your missing }, when your script.js file runs (in the <head> section), the rest of your document does not exist. The easiest way to work around this is to wrap your script in a document ready handler, eg

jQuery(function($) {
    $('#workerID').on('keyup', function() {
        alert('key up');
    });
});

Alternatively, you could move your script to the bottom of the document, eg

        <script src="js/scripts.js"></script>
    </body>
</html>

or use event delegation which allows you to bind events to a parent element (or the document), eg

$(document).on('keyup', '#workerID', function() {
    alert('key up');
});



回答2:


You're missing the curly bracket to close the function:

$('#workerID').keyup(function() {
    alert('key up');
});

Errors like these are usually seen in the browser's JavaScript console.




回答3:


in HTML

inser id, name,vale in " "

<div class="loginForm">
  <p>Worker-ID:<input type="text" id="workerID" name="workerID" /></p>
  <p>Password:<input type="password"  id="workerPassword" name="workerPassword" /></p>
  <input type="submit" id="submitLogin" name="submitLogin" value="Log in"/>
</div>

in js

$('#workerID').keyup(function() {
       alert('key up');} // here you forget "}"
      );

demo




回答4:


Syntax is wrong see here

$( document ).ready(function() {
   $( "#workerID" ).keyup(function() {
    .....................
   });
});

change ); to });



来源:https://stackoverflow.com/questions/19373455/jquery-keyup-function-doesnt-work

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