问题
I'm trying to match a regular expression in Perl. My code looks like the following:
my $source = "Hello_[version]; Goodbye_[version]";
my $pattern = "Hello_[version]";
if ($source =~ m/$pattern/) {
print "Match found!"
}
The problem arises in that brackets indicate a character class (or so I read) when Perl tries to match the regex, and the match ends up failing. I know that I can escape the brackets with \[
or \]
, but that would require another block of code to go through the string and search for the brackets. Is there a way to have the brackets automatically ignored without escaping them individually?
Quick note: I can't just add the backslash, as this is just an example. In my real code, $source
and $pattern
are both coming from outside the Perl code (either URIEncoded or from a file).
回答1:
You are using the Wrong Tool for the job.
You do not have a pattern! There are NO regex characters in $pattern!
You have a literal string.
index() is for working with literal strings...
my $source = "Hello_[version]; Goodbye_[version]";
my $pattern = "Hello_[version]";
if ( index($source, $pattern) != -1 ) {
print "Match found!";
}
回答2:
\Q
will disable metacharacters until \E
is found or the end of the pattern.
my $source = "Hello_[version]; Goodbye_[version]";
my $pattern = "Hello_[version]";
if ($source =~ m/\Q$pattern/) {
print "Match found!"
}
http://www.anaesthetist.com/mnm/perl/Findex.htm
回答3:
Use quotemeta():
my $source = "Hello_[version]; Goodbye_[version]";
my $pattern = quotemeta("Hello_[version]");
if ($source =~ m/$pattern/) {
print "Match found!"
}
回答4:
You can escape set of special characters in an expression by using the following command.
expression1 = 'text with special characters like $ % ( )';
expression1 =~s/[\?*+\^\$[]\(){}\|-]/"\$&"/eg ;
This will escape all the special characters
print "expression1'; # text with special characters like \$ \% ( )
来源:https://stackoverflow.com/questions/7423143/escaping-special-characters-in-perl-regex