Django Comments: Want to remove user URL, not expand the model. How to?

谁说我不能喝 提交于 2019-12-30 03:03:09

问题


I'm totally understanding the documentation on expanding the Comments app in Django, and really would like to stick with the automatic functionality but...

In the current app, I have absolutely no use for an "URL" to be submitted along with a comment.

Being minimally invasive of the default setup, how can I prevent this field from showing up with the comment form?

Using Django 1, or Trunk, and as many generic/built-ins as possible (generic views, default comments set up, etc. I have only a single generic view wrapper so far).


回答1:


This is well documented under customizing the comments framework.

All your app will use is get_form, returning a subclass of the CommentForm with the url field popped. Something like:

class NoURLCommentForm(CommentForm):
    """
    A comment form which matches the default djanago.contrib.comments one, but
    doesn't have a URL field.

    """
NoURLCommentForm.base_fields.pop('url')



回答2:


I can't comment onto SmileyChris' post for some reason, so I am going to post it here. But, I ran into errors using just SmileyChris' response. You also have to overwrite the get_comment_create_data function because CommentForm is going to look for those Post keys that you removed. So here's my code after I removed three fields.

class SlimCommentForm(CommentForm):
"""
A comment form which matches the default djanago.contrib.comments one, but with 3 removed fields
"""
def get_comment_create_data(self):
    # Use the data of the superclass, and remove extra fields
    return dict(
        content_type = ContentType.objects.get_for_model(self.target_object),
        object_pk    = force_unicode(self.target_object._get_pk_val()),
        comment      = self.cleaned_data["comment"],
        submit_date  = datetime.datetime.now(),
        site_id      = settings.SITE_ID,
        is_public    = True,
        is_removed   = False,
    )


SlimCommentForm.base_fields.pop('url')
SlimCommentForm.base_fields.pop('email')
SlimCommentForm.base_fields.pop('name')

This is the function that you are overwriting

def get_comment_create_data(self):
    """
    Returns the dict of data to be used to create a comment. Subclasses in
    custom comment apps that override get_comment_model can override this
    method to add extra fields onto a custom comment model.
    """
    return dict(
        content_type = ContentType.objects.get_for_model(self.target_object),
        object_pk    = force_unicode(self.target_object._get_pk_val()),
        user_name    = self.cleaned_data["name"],
        user_email   = self.cleaned_data["email"],
        user_url     = self.cleaned_data["url"],
        comment      = self.cleaned_data["comment"],
        submit_date  = datetime.datetime.now(),
        site_id      = settings.SITE_ID,
        is_public    = True,
        is_removed   = False,
    )



回答3:


My quick and dirty solution: I made the the 'email' and 'url' fields hidden fields, with an arbitrary value to get rid of 'this field is required' errors.

It's not elegant, but it's quick and I didn't have to subclass CommentForm. All the work of adding comments was done in the template, which is nice. It looks like this (warning: not tested, since it's a simplified version of my actual code):

{% get_comment_form for entry as form %}

<form action="{% comment_form_target %}" method="post"> {% csrf_token %}

{% for field in form %}

    {% if field.name != 'email' and field.name != 'url' %}
        <p> {{field.label}} {{field}} </p>
    {% endif %}

{% endfor %}

    <input type="hidden" name="email" value="foo@foo.foo" />
    <input type="hidden" name="url" value="http://www.foofoo.com" />

    <input type="hidden" name="next" value='{{BASE_URL}}thanks_for_your_comment/' />
    <input type="submit" name="post" class="submit-post" value="Post">
</form>


来源:https://stackoverflow.com/questions/1456267/django-comments-want-to-remove-user-url-not-expand-the-model-how-to

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