Gson serialize POJO with root value included?

问题

I'm having a problem serializing an object using Gson.

@XmlRootElement
class Foo implements Serializable {
    private int number;
    private String str;

    public Foo() {
        number = 10;
        str = "hello";
    }
}

Gson will serialize this into a JSON

{"number":10,"str":"hello"}.

However, I want it to be

{"Foo":{"number":10,"str":"hello"}},

so basically including the top level element. I tried to google a way to do this in Gson, but no luck. Anyone knows if there is a way to achieve this?

Thanks!

回答1:

You need to add the element at the top of the the object tree. Something like this:

Gson gson = new Gson();
JsonElement je = gson.toJsonTree(new Foo());
JsonObject jo = new JsonObject();
jo.add("Foo", je);
System.out.println(jo.toString());
// Prints {"Foo":{"number":10,"str":"hello"}}

回答2:

Instead of hardcoding the type you can do:

...
jo.add(Foo.getClass().getSimpleName(), je);

回答3:

A better way to do this is to create a wrapper class and then create an object of Foo inside it.

Sample code:

public class ResponseWrapper {

   @SerializedName("Foo")
   private Foo foo;

   public Foo getFoo() {
      return foo;
   }

   public void setFoo(Foo foo) {
      this.foo= foo;
   }
 }

Then you can easily parse to JSON using:

new GsonBuilder().create().toJson(responseWrapperObj);

which will give you the desired structure:

{"Foo":{"number":10,"str":"hello"}}

回答4:

If you are using Jackson api use the below lines

mapper.configure(SerializationFeature.WRAP_ROOT_VALUE, true); mapper.configure(DeserializationFeature.UNWRAP_ROOT_VALUE, true);

来源：https://stackoverflow.com/questions/4623329/gson-serialize-pojo-with-root-value-included

标签

java

json

serialization

gson