Unlimited arguments for PHP function?

问题

In php how would you create a function that could take an unlimited number of parameters: myFunc($p1, $p2, $p3, $p4, $p5...);

My next question is: how would you pass them into another function something like

function myFunc($params){
  anotherFunc($params);
}

but the anotherFunc would receive them as if it was called using anotherFunc($p1, $p2, $p3, $p4, $p5...)

回答1:

call_user_func_array('anotherFunc', func_get_args());

func_get_args returns an array containing all arguments passed to the function it was called from, and call_user_func_array calls a given function, passing it an array of arguments.

回答2:

Previously you should have used func_get_args(), but in a new php 5.6 (currently in beta), you can use ... operator instead of using .

So for example you can write :

function myFunc(...$el){
  var_dump($el); 
}

and $el will have all the elements you will pass.

回答3:

Is there a reason why you couldn't use 1 function argument and pass all the info through as an array?

回答4:

Check out the documentation for variable-length argument lists for PHP.

The second part of your question refers to variable functions:

...if a variable name has parentheses appended to it, PHP will look for a function with the same name as whatever the variable evaluates to, and will attempt to execute it.

来源：https://stackoverflow.com/questions/5009382/unlimited-arguments-for-php-function