JPA query equals between two properties

问题

It is possible to compare two properties with JPA custom query ?

Registration.java :

@Entity
public class Registration implements Serializable {

@Id
@GeneratedValue(generator = "uuid")
private UUID uuid;

@ManyToOne(targetEntity=Entry.class)
private Entry entry;

@ManyToMany(targetEntity=Rate.class,fetch = FetchType.EAGER)
private List<Rate> rate;

@ManyToMany(fetch = FetchType.EAGER)
private List<Planning> planning;

}

Rate.java :

@Entity
public class Rate implements Serializable {

@Id
@GeneratedValue(generator = "uuid")
private UUID uuid;

@ManyToOne
private Activity activity;
}

Planning.java :

@Entity
public class Planning implements Serializable {

@Id
@GeneratedValue(generator = "uuid")
private UUID uuid;

@OneToOne
private Location location;

@OneToOne(fetch = FetchType.EAGER)
private Coach coach;

@OneToOne
private Activity activity;

I would retrieve only rate.activity.id = planning.activity.id with something like :

public interface RegistrationDao extends CrudRepository<Registration, UUID> {

    findByPlanningAndRateActivityEqualsPlanningActivityOrderByEntryLastnameAsc(Planning planning);

 }

Thanks

回答1:

Rather than having a long method name you can have a JPA Query it will be something like this. Hope this helps.

@Query("select * FROM Registration REG,Entry E, Rate R,Planning P WHERE REG.id = :id and R.activity=P.activity ORDER BY E.lastname")

public List<Registration> <MethodName>(@Param("id") String registrationid);

回答2:

I have changed for this solution but I dont think that is the good approach (where rateActivity and planningActivity have to have the same id)

public interface RegistrationDao extends CrudRepository<Registration, UUID> {

  Iterable<Registration> findByPlanningAndRateActivityEqualsAndPlanningActivityEqualsOrderByEntryLastnameAsc(Planning planning,Activity rateActivity,Activity planningActivity);

}

来源：https://stackoverflow.com/questions/35989046/jpa-query-equals-between-two-properties