Using JQuery getJSON method

问题

I am attempting to pase a a JSON data using the JQuery getJSON function. The REST query is:

http://query.yahooapis.com/v1/public/yql?q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22london%22&format=json&jsoncallback=?

The script I'm using to parse 'data' to obtain the WOEID value doesnt seem to work below:

 $.getJSON("http://query.yahooapis.com/v1/public/yql?"+
                "q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22"+
                "london"+
                "%22&format=json&jsoncallback=?",
        function(data){
  console.log("json: " + data);
  var datatmp = data;
          if(data.results[0]){
            var data = filterData(data.results.place[0]);
           }
         }
       );

Can anyone say what I'm doing wrong? link text

回答1:

Your code needed a few tweaks, here's an updated version:

$.getJSON("http://query.yahooapis.com/v1/public/yql?"+
      "q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22"+
      "london"+
      "%22&format=json&jsoncallback=json",
      function(data){
          if(data.query.results){
              $.each(data.query.results.place, function(i, v) {
                  console.log("woeid #" + i + ": " + v["woeid"]);
              });
          }
      });

The results object is beneath query, so you need to go into there first, the above code iterates through the woeid's of the first place returned and alerts them...it's just a starter, not sure what you ultimately wanted to do with the woeid but hopefully this will get you started. You can see the above code working here.

回答2:

In this line:

      if(data.results[0]){
        var data = filterData(data.results.place[0]);
       }

You check to see if results[0] exists but then you don't use it. I suspect your problem would be fixed by changing to this:

      if(data.results[0]){
        var data = filterData(data.results[0].place[0]);
       }

回答3:

You have two key mistakes:

The correct parameter for specifying the callback in the YQL URL is callback rather than jsoncallback
The results are to be found in data.query.results… rather than data.results…

Also it is worth noting that there is a data.query.count value returned with the YQL results so you can see how many results were returned.

回答4:

I have a question: can you access that URL (http://query.yahooapis.com/...) even if it's not in your domain? Doesn't that violate the "same origin policy"?

来源：https://stackoverflow.com/questions/2604082/using-jquery-getjson-method

标签

jquery

json

getjson