问题
I want to make a binary tree zipper an instance of comonad, but I can't figure out how to implement duplicate properly.
Here is my attempt:
{-# LANGUAGE DeriveFunctor #-}
import Data.Function
import Control.Arrow
import Control.Comonad
data BinTree a
= Leaf a
| Branch a (BinTree a) (BinTree a)
deriving (Functor, Show, Eq)
data Dir = L | R
deriving (Show, Eq)
-- an incomplete binary tree, aka data context
data Partial a = Missing Dir (BinTree a) a
deriving (Show, Eq, Functor)
-- BTZ for BinTree Zipper
newtype BTZ a = BTZ { getBTZ :: ([Partial a], BinTree a) }
deriving (Show, Eq)
instance Functor BTZ where
fmap f (BTZ (cs,t)) = BTZ (map (fmap f) cs, fmap f t)
-- | replace every node label with the zipper focusing on that node
dup :: BinTree a -> BinTree (BTZ a)
dup (Leaf v) = Leaf (BTZ ([], Leaf v))
dup t@(Branch v tl tr) = Branch (BTZ ([],t)) tlZ trZ
where
tlZ = fmap (BTZ . first (++ [Missing L tr v]) . getBTZ) (dup tl)
trZ = fmap (BTZ . first (++ [Missing R tl v]) . getBTZ) (dup tr)
-- | extract root label
rootVal :: BinTree a -> a
rootVal (Leaf v) = v
rootVal (Branch v _ _) = v
-- | move zipper focus around
goUp, goLeft, goRight :: BTZ a -> BTZ a
goUp (BTZ ([], _)) = error "already at root"
goUp (BTZ (Missing wt t2 v:xs, t1)) = case wt of
L -> BTZ (xs, Branch v t1 t2)
R -> BTZ (xs, Branch v t2 t1)
goLeft z = let (cs,t) = getBTZ z in
case t of
Leaf _ -> error "already at leaf"
Branch v t1 t2 -> BTZ (Missing L t2 v:cs, t1)
goRight z = let (cs,t) = getBTZ z in
case t of
Leaf _ -> error "already at leaf"
Branch v t1 t2 -> BTZ (Missing R t1 v:cs, t2)
instance Comonad BTZ where
extract (BTZ (_,t)) =
case t of
Leaf v -> v
Branch v _ _ -> v
duplicate z@(BTZ (cs, bt)) = case bt of
Leaf _ -> BTZ (csZ, Leaf z) -- extract . duplicate = id
Branch v tl tr ->
-- for each subtree, use "dup" to build zippers,
-- and attach the current focusing root(bt) and rest of the data context to it
let tlZ = fmap (BTZ . first (++Missing L tr v :cs) . getBTZ) (dup tl)
trZ = fmap (BTZ . first (++Missing R tl v :cs) . getBTZ) (dup tr)
in BTZ (csZ, Branch z tlZ trZ)
where
-- go up and duplicate, we'll have a "BTZ (BTZ a)"
-- from which we can grab "[Partial (BTZ a)]" out
-- TODO: not sure if it works
upZippers = take (length cs-1) . tail $ iterate goUp z
csZ = fmap (head . fst . getBTZ . duplicate) upZippers
main :: IO ()
main = do
let tr :: BTZ Int
tr = rootVal $ dup (Branch 1 (Leaf 2) (Branch 3 (Leaf 4) (Leaf 5)))
equalOnTr :: Eq a => (BTZ Int -> a) -> (BTZ Int -> a) -> Bool
equalOnTr = (==) `on` ($ tr)
print $ (extract . duplicate) `equalOnTr` id
print $ (fmap extract . duplicate) `equalOnTr` id
print $ (duplicate . duplicate) `equalOnTr` (fmap duplicate . duplicate)
Some explanation:
BinTree ais the binary tree data type and each tree node contains a label.Partial ais a binary tree with either left or right subtree. A stack ofPartial ain my code plays the role of data context.BTZstands for theBinTreezipper, which I want to make an instance ofComonad, it consists of a data context and the focusing subtree.
To make it an instance of Comonad, my plan is to implement extract and duplicate, and verify if the comonad properties hold by taking some random binary trees.
The extract is straightforward, just taking the focusing subtree out.
Function dup serves as an auxiliary function that replaces each node label
with the tree zipper focusing on that node.
For duplicate z, the node label needs to be z itself so that extract . duplicate == id holds. For non-leaf nodes, I use dup to deal with their subtrees as if they have no parents, and the current focus of z and the rest of the data context gets appended to these zippers afterwards.
So far the first two comonad properties are satisfied (extract . duplicate = id and fmap extract . duplicate), but I have no idea what to do with the data context. What I currently do is taking the zipper z and keep going up. Along the way we take the top of each data context stack to build the new data context stack, which sounds right to be and also is of the correct type ([Partial (BTZ a)]. But my approach cannot satisfy the third law.
Given the data type definition of binary tree zipper above, is it possible to make it an instance of Comonad? If the answer is yes, is there something wrong with my approach?
回答1:
In the differential calculus, Leibniz's notation causes less confusion than Newton's because it is explicit about the variable with respect to which we differentiate. Contexts in things are given by differentiation, so we must take care what is being contextualized. Here, there are two notions of "substructure" at work: subtrees and elements. They each have different (but related) notions of "context" and hence of "zipper", where a zipper is the pair of a thing and its context.
Your BTZ type is presented as the notion of zipper for subtrees. However, the zipper comonadic construction works on zippers for elements: extract means "give element here"; duplicate means "decorate each element with its context". So you need element contexts. Confusingly, for these binary trees, element zippers and subtree zippers are isomorphic, but that is for a very particular reason (namely that they form a cofree comonad).
Generally, element- and subtree-zippers differ, e.g., for lists. If we start by building the element-zipper comonad for lists, we are less likely to get lost when we come back to trees. Let me try also to fill in a bit more of the general picture, for others as well as yourself.
Sublist contexts
The sublist-contexts for [a] are just given by [a], being the list of elements we pass by on the way out from the sublist to the whole list. The sublist context for [3,4] in [1,2,3,4] is [2,1]. Subnode contexts for recursive data are always lists representing what you see on the path from the node to the root. The type of each step is given by the partial derivative of the formula for one node of data with respect to the recursive variable. So here
[a] = t where -- t is the recursive variable standing for [a]
t = 1 + a*t -- lists of a are either [] or an (a : t) pair
∂/∂t (1 + a*t) = a -- that's one step on a path from node to root
sublist contexts are [a] -- a list of such steps
So a sublist-zipper is a pair
data LinLZ a = LinLZ
{ subListCtxt :: [a]
, subList :: [a]
}
We can write the function which plugs a sublist back into its context, reversing back up the path
plugLinLZ :: LinLZ a -> [a]
plugLinLZ (LinLZ { subListCtxt = [], subList = ys}) = ys
plugLinLZ (LinLZ { subListCtxt = x : xs, subList = ys})
= plugLinLZ (LinLZ { subListCtxt = xs, subList = x : ys})
But we can't make LinLZ a Comonad, because (for example) from
LinLZ { subListCtxt = [], subList = [] }
we can't extract an element (an a from LinLZ a), only a sublist.
List Element Contexts
A list element context is a pair of lists: the elements before the element in focus, and the elements after it. An element context in a recursive structure is always a pair: first give the subnode-context for the subnode where the element is stored, then give the context for the element in its node. We get the element-in-its-node context by differentiating the formula for a node with respect to the variable which stands for elements.
[a] = t where -- t is the recursive variable standing for [a]
t = 1 + a*t -- lists of a are either [] or an (a : t) pair
∂/∂a (1 + a*t) = t = [a] -- the context for the head element is the tail list
So an element context is given by a pair
type DL a =
( [a] -- the sublist context for the node where the element is
, [a] -- the tail of the node where the element is
)
and an element zipper is given by pairing such a context with the element "in the hole".
data ZL a = ZL
{ this :: a
, between :: DL a
} deriving (Show, Eq, Functor)
You can turn such a zipper back into a list (going "out" from an element) by first reconstituting the sublist where the element sits, giving us a sublist zipper, then plugging the sublist into its sublist-context.
outZL :: ZL a -> [a]
outZL (ZL { this = x, between = (zs, xs) })
= plugLinLZ (LinLZ { subListCtxt = zs, subList = x : xs })
Putting each element into context
Given a list, we can pair each element up with its context. We get the list of ways we can "go into" one of the elements. We start like this,
into :: [a] -> [ZL a]
into xs = moreInto (LinLZ { subListCtxt = [], subList = xs })
but the real work is done by the helper function which works on a list-in-context.
moreInto :: LinLZ a -> [ZL a]
moreInto (LinLZ { subListCtxt = _, subList = [] }) = []
moreInto (LinLZ { subListCtxt = zs, subList = x : xs })
= ZL { this = x, between = (zs, xs) }
: moreInto (LinLZ { subListCtxt = x : zs, subList = xs })
Notice that the output echoes the shape of the current subList. Also, the zipper in x's place has
this = x. Also, the generating zipper for decorating xs has subList = xs and the correct context,
recording that we have moved past x. Testing,
into [1,2,3,4] =
[ ZL {this = 1, between = ([],[2,3,4])}
, ZL {this = 2, between = ([1],[3,4])}
, ZL {this = 3, between = ([2,1],[4])}
, ZL {this = 4, between = ([3,2,1],[])}
]
Comonadic structure for list element zippers
We've seen how to go out from an element, or into one of the available elements. The comonadic structure tells us how to move between elements, either staying where we are, or moving to one of the others.
instance Comonad ZL where
The extract gives us the element we're visiting.
extract = this
To duplicate a zipper, we replace the current element x with the whole current zipper zl (whose this = x)...
duplicate zl@(ZL { this = x, between = (zs, ys) }) = ZL
{ this = zl
...and we work our way through the context, showing how to refocus at each element. Our existing moreInto lets us move inward, but we must also move outward...
, between =
( outward (LinLZ { subListCtxt = zs, subList = x : ys })
, moreInto (LinLZ { subListCtxt = x : zs, subList = ys })
)
}
...which involves travelling back along the context, moving elements into the sublist, as follows
where
outward (LinLZ { subListCtxt = [], subList = _ }) = []
outward (LinLZ { subListCtxt = z : zs, subList = ys })
= ZL { this = z, between = (zs, ys) }
: outward (LinLZ { subListCtxt = zs, subList = z : ys })
So we get
duplicate ZL {this = 2, between = ([1],[3,4])}
= ZL
{ this = ZL {this = 2, between = ([1],[3,4])}
, between =
( [ ZL {this = 1, between = ([],[2,3,4])} ]
, [ ZL {this = 3, between = ([2,1],[4])}
, ZL {this = 4, between = ([3,2,1],[])}
]
)
}
where this is "staying at 2" and we are between "moving to 1" and "moving to 3 or moving to 4".
So, the comonadic structure shows us how we can move between different elements located inside a list. The sublist structure plays a key role in finding the nodes where the elements are, but the zipper structure duplicated is an element zipper.
So what about trees?
Digression: labelled trees are comonads already
Let me refactor your type of binary trees to bring out some structure. Literally, let us pull the element which labels a leaf or a fork out as a common factor. Let us also isolate the functor (TF) which explains this leaf-or-fork subtree structure.
data TF t = Leaf | Fork (t, t) deriving (Show, Eq, Functor)
data BT a = a :& TF (BT a) deriving (Show, Eq, Functor)
That is, every tree node has a label, whether it is a leaf or a fork.
Wherever we have the structure that every node has a label and a blob of substructures, we have a comonad: the cofree comonad. Let me refactor a little more, abstracting out TF...
data CoFree f a = a :& f (CoFree f a) deriving (Functor)
...so we have a general f where we had TF before. We can recover our specific trees.
data TF t = Leaf | Fork (t, t) deriving (Show, Eq, Functor)
type BT = CoFree TF
deriving instance Show a => Show (BT a)
deriving instance Eq a => Eq (BT a)
And now, once for all, we can give the cofree comonad construction. As every subtree has a root element, every element can be decorated with the tree whose root it is.
instance Functor f => Comonad (CoFree f) where
extract (a :& _) = a -- extract root element
duplicate t@(a :& ft) = t :& fmap duplicate ft -- replace root element by whole tree
Let's have an example
aTree =
0 :& Fork
( 1 :& Fork
( 2 :& Leaf
, 3 :& Leaf
)
, 4 :& Leaf
)
duplicate aTree =
(0 :& Fork (1 :& Fork (2 :& Leaf,3 :& Leaf),4 :& Leaf)) :& Fork
( (1 :& Fork (2 :& Leaf,3 :& Leaf)) :& Fork
( (2 :& Leaf) :& Leaf
, (3 :& Leaf) :& Leaf
)
, (4 :& Leaf) :& Leaf
)
See? Each element has been paired with its subtree!
Lists do not give rise to a cofree comonad, because not every node has an element: specifically, [] has no element. In a cofree comonad, there is always an element where you are, and you can see further down into the tree structure, but not further up.
In an element zipper comonad, there is always an element where you are, and you can see both up and down.
Subtree and element contexts in binary trees
Algebraically
d/dt (TF t) = d/dt (1 + t*t) = 0 + (1*t + t*1)
so we may define
type DTF t = Either ((), t) (t, ())
saying that a subtree inside the "blob of substructures" is either on the left or the right. We can check that "plugging in" works.
plugF :: t -> DTF t -> TF t
plugF t (Left ((), r)) = Fork (t, r)
plugF t (Right (l, ())) = Fork (l, t)
If we instantiate t and pair up with the node label, we get one step of subtree context
type BTStep a = (a, DTF (BT a))
which is isomorphic to Partial in the question.
plugBTinBT :: BT a -> BTStep a -> BT a
plugBTinBT t (a, d) = a :& plugF t d
So, a subtree-context for one BT a inside another is given by [BTStep a].
But what about an element context? Well, every element labels some subtree, so we should record both that subtree's context and the rest of the tree labelled by the element.
data DBT a = DBT
{ below :: TF (BT a) -- the rest of the element's node
, above :: [BTStep a] -- the subtree context of the element's node
} deriving (Show, Eq)
Annoyingly, I have to roll my own Functor instance.
instance Functor DBT where
fmap f (DBT { above = a, below = b }) = DBT
{ below = fmap (fmap f) b
, above = fmap (f *** (either
(Left . (id *** fmap f))
(Right . (fmap f *** id)))) a
}
Now I can say what an element zipper is.
data BTZ a = BTZ
{ here :: a
, ctxt :: DBT a
} deriving (Show, Eq, Functor)
If you're thinking "what's new?", you're right. We have a subtree context, above, together with a subtree given by here and below. And that's because the only elements are those which label nodes.
Splitting a node up into an element and its context is the same as splitting it into its label and its blob of substructures. That is, we get this coincidence for cofree comonads, but not in general.
However, this coincidence is only a distraction! As we saw with lists, we don't need element-zippers to be the same as subnode-zippers to make element-zippers a comonad.
Following the same pattern as lists above, we can decorate every element with its context. The work is done by a helper function which accumulates the subtree context we are currently visiting.
down :: BT a -> BT (BTZ a)
down t = downIn t []
downIn :: BT a -> [BTStep a] -> BT (BTZ a)
downIn (a :& ft) ads =
BTZ { here = a, ctxt = DBT { below = ft, above = ads } }
:& furtherIn a ft ads
Note that a is replaced by a zipper focused on a. The subtrees are handled by another helper.
furtherIn :: a -> TF (BT a) -> [BTStep a] -> TF (BT (BTZ a))
furtherIn a Leaf ads = Leaf
furtherIn a (Fork (l, r)) ads = Fork
( downIn l ((a, Left ((), r)) : ads)
, downIn r ((a, Right (l, ())) : ads)
)
See that furtherIn preserves the tree structure, but grows the subtree context suitably when it visits a subtree.
Let's double check.
down aTree =
BTZ { here = 0, ctxt = DBT {
below = Fork (1 :& Fork (2 :& Leaf,3 :& Leaf),4 :& Leaf),
above = []}} :& Fork
( BTZ { here = 1, ctxt = DBT {
below = Fork (2 :& Leaf,3 :& Leaf),
above = [(0,Left ((),4 :& Leaf))]}} :& Fork
( BTZ { here = 2, ctxt = DBT {
below = Leaf,
above = [(1,Left ((),3 :& Leaf)),(0,Left ((),4 :& Leaf))]}} :& Leaf
, BTZ { here = 3, ctxt = DBT {
below = Leaf,
above = [(1,Right (2 :& Leaf,())),(0,Left ((),4 :& Leaf))]}} :& Leaf
)
, BTZ { here = 4, ctxt = DBT {
below = Leaf,
above = [(0,Right (1 :& Fork (2 :& Leaf,3 :& Leaf),()))]}} :& Leaf)
See? Each element is decorated with its whole context, not just the tree below it.
Binary tree zippers form a Comonad
Now that we can decorate elements with their contexts, let us build the Comonad instance. As before...
instance Comonad BTZ where
extract = here
...extract tells us the element in focus, and we can make use of our existing machinery to go further into the tree, but we need to build new kit to explore the ways we can move outwards.
duplicate z@(BTZ { here = a, ctxt = DBT { below = ft, above = ads }}) = BTZ
{ here = z
, ctxt = DBT
{ below = furtherIn a ft ads -- move somewhere below a
, above = go_a (a :& ft) ads -- go above a
}
} where
To go outwards, as with lists, we must move back along the path towards the root. As with lists, each step on the path is a place we can visit.
go_a t [] = []
go_a t (ad : ads) = go_ad t ad ads : go_a (plugBTinBT t ad) ads
go_ad t (a, d) ads =
( BTZ { here = a, ctxt = DBT { below = plugF t d, above = ads } } -- visit here
, go_d t a d ads -- try other subtree
)
Unlike with lists, there are alternative branches along that path to explore. Wherever the path stores an unvisited subtree, we must decorate its elements with their contexts.
go_d t a (Left ((), r)) ads = Left ((), downIn r ((a, Right (t, ())) : ads))
go_d t a (Right (l, ())) ads = Right (downIn l ((a, Left ((), t)) : ads), ())
So now we've explained how to refocus from any element position to any other.
Let's see. Here we were visiting 1:
duplicate (BTZ {here = 1, ctxt = DBT {
below = Fork (2 :& Leaf,3 :& Leaf),
above = [(0,Left ((),4 :& Leaf))]}}) =
BTZ {here = BTZ {here = 1, ctxt = DBT {
below = Fork (2 :& Leaf,3 :& Leaf),
above = [(0,Left ((),4 :& Leaf))]}}, ctxt = DBT {
below = Fork (BTZ {here = 2, ctxt = DBT {
below = Leaf,
above = [(1,Left ((),3 :& Leaf)),(0,Left ((),4 :& Leaf))]}} :& Leaf
,BTZ {here = 3, ctxt = DBT {
below = Leaf,
above = [(1,Right (2 :& Leaf,())),(0,Left ((),4 :& Leaf))]}} :& Leaf
),
above = [(BTZ {here = 0, ctxt = DBT {
below = Fork (1 :& Fork (2 :& Leaf,3 :& Leaf),4 :& Leaf),
above = []}}
,Left ((),BTZ {here = 4, ctxt = DBT {
below = Leaf,
above = [(0,Right (1 :& Fork (2 :& Leaf,3 :& Leaf),()))]}} :& Leaf)
)
]}}
By way of testing the comonad laws on a small sample of data, let us check:
fmap (\ z -> extract (duplicate z) == z) (down aTree)
= True :& Fork (True :& Fork (True :& Leaf,True :& Leaf),True :& Leaf)
fmap (\ z -> fmap extract (duplicate z) == z) (down aTree)
= True :& Fork (True :& Fork (True :& Leaf,True :& Leaf),True :& Leaf)
fmap (\ z -> fmap duplicate (duplicate z) == duplicate (duplicate z)) (down aTree)
= True :& Fork (True :& Fork (True :& Leaf,True :& Leaf),True :& Leaf)
来源：https://stackoverflow.com/questions/25519767/how-to-make-a-binary-tree-zipper-an-instance-of-comonad