How to give each instance its own row in a data frame? [duplicate]

问题

This question already has answers here:

Repeat each row of data.frame the number of times specified in a column (7 answers)

Closed last month.

How is it possible to transform this data frame so that the count is divided into separate observations?

df = data.frame(object = c("A","B", "A", "C"), count=c(1,2,3,2))

  object count
1      A     1
2      B     2
3      A     3
4      C     2

So that the resulting data frame looks like this?

  object observation
1      A           1
2      B           1
3      B           1
4      A           1
5      A           1
6      A           1
7      C           1
8      C           1

回答1:

rep(df$object, df$count)

If you want the 2 columns:

df2 = data.frame(object = rep(df$object, df$count))
df2$count = 1

回答2:

If you're working with tidyverse - otherwise that's overkill -, you could also do:

library(tidyverse)

uncount(df, count) %>% mutate(observation = 1)

回答3:

Using data.table:

library(data.table)
setDF(df)[rep(seq_along(count), count), .(object, count = 1L)]

   object count
1:      A     1
2:      B     1
3:      B     1
4:      A     1
5:      A     1
6:      A     1
7:      C     1
8:      C     1

来源：https://stackoverflow.com/questions/58661167/how-to-give-each-instance-its-own-row-in-a-data-frame