Can I set the umask for tempfile.NamedTemporaryFile in python?

问题

In Python (tried this in 2.7 and below) it looks like a file created using tempfile.NamedTemporaryFile doesn't seem to obey the umask directive:

import os, tempfile
os.umask(022)
f1 = open ("goodfile", "w")
f2 = tempfile.NamedTemporaryFile(dir='.')
f2.name

Out[33]: '/Users/foo/tmp4zK9Fe'

ls -l
-rw-------  1 foo  foo  0 May 10 13:29 /Users/foo/tmp4zK9Fe
-rw-r--r--  1 foo  foo  0 May 10 13:28 /Users/foo/goodfile

Any idea why NamedTemporaryFile won't pick up the umask? Is there any way to do this during file creation?

I can always workaround this with os.chmod(), but I was hoping for something that did the right thing during file creation.

回答1:

This is a security feature. The NamedTemporaryFile is always created with mode 0600, hardcoded at tempfile.py, line 235, because it is private to your process until you open it up with chmod. There is no constructor argument to change this behavior.

回答2:

In case it might help someone, I wanted to do more or less the same thing, here is the code I have used:

import os
from tempfile import NamedTemporaryFile

def UmaskNamedTemporaryFile(*args, **kargs):
    fdesc = NamedTemporaryFile(*args, **kargs)
    umask = os.umask(0)
    os.umask(umask)
    os.chmod(fdesc.name, 0o666 & ~umask)
    return fdesc

来源：https://stackoverflow.com/questions/10541760/can-i-set-the-umask-for-tempfile-namedtemporaryfile-in-python