xcode storyboard Container View - How do I access the viewcontroller

问题

I'm trying to use storyboard and get things working properly. I've added a a Container View to one of my existing views. When I try to add a reference to this in my view controller .h file (ctrl-drag), I get a IBOutlet UIView *containerView. How do I get a reference to the container view's view controller instead? I need the container view controller so I can set it's delegate to my view's controller so they can "talk" to each other.

I have my story board setup as:

And its referenced in my .h file as:

Notice in the .h that is is a UIView, not my InstallViewController for the view. How do I add a reference to the view controller? I need to be able to set its delegate.

回答1:

There is another solution by specifying an identifier for the embed segue(s) and retrieve the corresponding view controllers in method prepareForSegue:

The advantage of this way is that you needn't rely on a specific order in which your child view controllers are added due to the fact that each child view controller is embedded via an unique segue identifier.

Update 2013-01-17 - Example

- (void) prepareForSegue:(UIStoryboardSegue*)segue sender:(id)sender
{
    // -- Master View Controller
    if ([segue.identifier isEqualToString:c_SegueIdEmbedMasterVC])
    {
        self.masterViewController = segue.destinationViewController;
        // ...
    }
    // -- Detail View Controller
    else if ([segue.identifier isEqualToString:c_SegueIdEmbedDetailVC])
    {
        self.detailViewController = segue.destinationViewController;
        // ...
    }
}

c_SegueIdEmbedMasterVC & c_SegueIdEmbedDetailVC are constants with the corresponding ID of the segue IDs defined in the storyboard.

回答2:

When you add a container view the xcode calls the UIViewController method addChildViewController:

In your case, you can get the container ViewController looking for it on the SplashViewController's list of childViewControllers, something like this:

for (UIViewController *childViewController in [self childViewControllers])
{
    if ([childViewController isKindOfClass:[InstallViewController class]])
    {
        //found container view controller
        InstallViewController *installViewController = (InstallViewController *)childViewController;

        //do something with your container view viewcontroller

        break;
    }
}

I had the same doubt yesterday :)

回答3:

The answer of Vitor Franchi is correct but could be more performant and convenient. Especially when accessing the child view controller several times.

Create a readonly property

@interface MyViewController ()
@property (nonatomic, weak, readonly) InstallViewController *cachedInstallViewController;
@end

Then create a convenient getter method

- (InstallViewController *)installViewController
{
    if (_cachedInstallViewController) return _cachedInstallViewController;

    __block InstallViewController *blockInstallViewController = nil;
    NSArray *childViewControllers = self.childViewControllers;
    [childViewControllers enumerateObjectsUsingBlock:^(id childViewController, NSUInteger idx, BOOL *stop) {

        if ([childViewController isMemberOfClass:InstallViewController.class])
        {
            blockInstallViewController = childViewController;
            *stop = YES;
        }
    }];

    _cachedInstallViewController = blockInstallViewController;

    return _cachedInstallViewController;
}

From now on access the child view controller that way

[self.installViewController doSomething];

回答4:

UIView* viewInsideOfContainer = installerView.subviews[0];

Will give you the UIView inside of the UIViewController that your controller UIView references. You can cast the subview to any type that inherits from UIView.

回答5:

If the nib is loaded it will call addChildViewController as part of the initialisation process

so a performant solution could be also to overwrite

- (void)addChildViewController:(UIViewController *)childController

there you can catch your childController e.g. by comparing its Class and assign it to a property / ivar

-(void)addChildViewController:(UIViewController *)childController
{
    [super addChildViewController:childController];

    if([childController isKindOfClass:[InstallViewController class]])
    {
        self.installViewController = (InstallViewController *)childController;
    }

}

This will save your from iterating trough the childViewControllers.

来源：https://stackoverflow.com/questions/13275112/xcode-storyboard-container-view-how-do-i-access-the-viewcontroller