PowerShell - Password Generator - How to always include number in string?

问题

I have the following PowerShell script that creates a random string of 15 digits, for use as an Active Directory password.

The trouble is, this works great most of the time, but on some occasions it doesn't use a number or symbol. I just get 15 letters. This is then not usable as an Active Directory password, as it must have at least one number or symbol in it.

$punc = 46..46
$digits = 48..57
$letters = 65..90 + 97..122
$YouShallNotPass = get-random -count 15 `
-input ($punc + $digits + $letters) |
% -begin { $aa = $null } `
-process {$aa += [char]$_} `
-end {$aa}

Write-Host "Password is $YouShallNotPass"

How would I amend the script to always have at least one random number or symbol in it?

Thank you.

回答1:

You could invoke the Get-Random cmdlet three times, each time with a different input parameter (punc, digit and letters), concat the result strings and shuffle them using another Get-Random invoke:

 (Get-Random -Count 15 -InputObject ([char[]]$yourPassword)) -join ''

However, why do you want to reinvent the wheel? Consider using the following GeneratePassword function:

[Reflection.Assembly]::LoadWithPartialName("System.Web")
[System.Web.Security.Membership]::GeneratePassword(15,2)

And to ensure, it contains at least one random number (you already specify the number of symbols):

do {
   $pwd = [System.Web.Security.Membership]::GeneratePassword(15,2)
} until ($pwd -match '\d')

回答2:

As suggested by jisaak, there is no 100% guaranty that the Membership.GeneratePassword Method generates a password that meets the AD complexity requirements.

That's why I reinvented the wheel:

Function MakeUp-String([Int]$Size = 8, [Char[]]$CharSets = "ULNS", [Char[]]$Exclude) {
    $Chars = @(); $TokenSet = @()
    If (!$TokenSets) {$Global:TokenSets = @{
        U = [Char[]]'ABCDEFGHIJKLMNOPQRSTUVWXYZ'                                #Upper case
        L = [Char[]]'abcdefghijklmnopqrstuvwxyz'                                #Lower case
        N = [Char[]]'0123456789'                                                #Numerals
        S = [Char[]]'!"#$%&''()*+,-./:;<=>?@[\]^_`{|}~'                         #Symbols
    }}
    $CharSets | ForEach {
        $Tokens = $TokenSets."$_" | ForEach {If ($Exclude -cNotContains $_) {$_}}
        If ($Tokens) {
            $TokensSet += $Tokens
            If ($_ -cle [Char]"Z") {$Chars += $Tokens | Get-Random}             #Character sets defined in upper case are mandatory
        }
    }
    While ($Chars.Count -lt $Size) {$Chars += $TokensSet | Get-Random}
    ($Chars | Sort-Object {Get-Random}) -Join ""                                #Mix the (mandatory) characters and output string
}; Set-Alias Create-Password MakeUp-String -Description "Generate a random string (password)"

Usage:

The Size parameter defines the length of the password.
The CharSets parameter define the complexity where the character U, L, N and S stands for Uppercase, Lowercase, Numerals and Symbols. If supplied in lowercase (u, l, n or s) the returned string might contain any of character in the concerned character set, If supplied in uppercase (U, L, N or S) the returned string will contain at least one of the characters in the concerned character set.
The Exclude parameter lets you exclude specific characters that might e.g. lead to confusion like an alphanumeric O and a numeric 0 (zero).

Examples:

To create a password with a length of 8 characters that might contain any uppercase characters, lowercase characters and numbers:

Create-Password 8 uln

To create a password with a length of 12 characters that that contains at least one uppercase character, one lowercase character, one number and one symbol and does not contain the characters OLIoli01:

Create-Password 12 ULNS "OLIoli01"

_{For the latest Create-Password version, see: https://powersnippets.com/create-password/}

回答3:

Command to Generate Random passwords by using existing funciton:

[system.web.security.membership]::GeneratePassword(x,y)

x = Length of the password
y = Complexity

General Error:

Unable to find type [system.web.security.membership]. Make sure that the assembly that contains this type is loaded.

Solution:

Run the below command:

Add-Type -AssemblyName System.web;

回答4:

Another solution:

function New-Password() {
    param(
        [int] $Length = 10,
        [bool] $Upper = $true,
        [bool] $Lower = $true,
        [bool] $Numeric = $true,
        [string] $Special
    )

    $upperChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    $lowerChars = "abcdefghijklmnopqrstuvwxyz"
    $numericChars = "0123456789"

    $all = ""
    if ($Upper) { $all = "$all$upperChars" }
    if ($Lower) { $all = "$all$lowerChars" }
    if ($Numeric) { $all = "$all$numericChars" }
    if ($Special -and ($special.Length -gt 0)) { $all = "$all$Special" }

    $password = ""
    for ($i = 0; $i -lt $Length; $i++) {
        Write-Host "password: [$password]"
        $password = $password + $all[$(Get-Random -Minimum 0 -Maximum $all.Length)]
    }

    $valid = $true
    if ($Upper -and ($password.IndexOfAny($upperChars.ToCharArray()) -eq -1)) { $valid = $false }
    if ($Lower -and ($password.IndexOfAny($lowerChars.ToCharArray()) -eq -1)) { $valid = $false }
    if ($Numeric -and ($password.IndexOfAny($numericChars.ToCharArray()) -eq -1)) { $valid = $false }
    if ($Special -and $Special.Length -gt 1 -and ($password.IndexOfAny($Special.ToCharArray()) -eq -1)) { $valid = $false }

    if (-not $valid) {
        $password = New-Password `
            -Length $Length `
            -Upper $Upper `
            -Lower $Lower `
            -Numeric $Numeric `
            -Special $Special
    }

    return $password
}

Flexible enough to set length, turn on/of upper, lower, and numeric, and set the list of specials.

回答5:

I had the same issue here is the snippet I used to create my alphanumerical password its simple all I have done is used ASCII regex replace to make it nice.

Function Password-Generator ([int]$Length)
{
# Generate passwords just call password-generator(lenght of password)
$Assembly = Add-Type -AssemblyName System.Web
$RandomComplexPassword = [System.Web.Security.Membership]::GeneratePassword($Length,2)
$AlphaNumericalPassword = $RandomComplexPassword -replace '[^\x30-\x39\x41-\x5A\x61-\x7A]+'
Write-Output $AlphaNumericalPassword
}

回答6:

My take on generating passwords in PowerShell, based on what I've found here and in the Internets:

#Requires -Version 4.0
[CmdletBinding(PositionalBinding=$false)]
param (
    [Parameter(
        Mandatory = $false,
        HelpMessage = "Minimum password length"
    )]
    [ValidateRange(1,[int]::MaxValue)]
    [int]$MinimumLength = 24,

    [Parameter(
        Mandatory = $false,
        HelpMessage = "Maximum password length"
    )]
    [ValidateRange(1,[int]::MaxValue)]
    [int]$MaximumLength = 42,

    [Parameter(
        Mandatory = $false,
        HelpMessage = "Characters which can be used in the password"
    )]
    [ValidateNotNullOrEmpty()]
    [string]$Characters = '1234567890qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM@#%*-_+:,.'
)

(1..(Get-Random -Minimum $MinimumLength -Maximum $MaximumLength) `
| %{ `
    $Characters.GetEnumerator() | Get-Random `
}) -join ''

I preferred this over using System.Web, not to introduce dependencies, which could change with .Net / .Net Core versions.
My variation also allows random password length (in specified range), is fairly concise (apart from the parameters section, which is quite verbose, to enforce some validations and provide defaults) and allows character repetitions (as opposite to the code in the question, which never repeats the same character).

I understand, that this does not guarantee a digit in the password. This however can be addressed in different ways. E.g. as was suggested, to repeat the generation until the password matches the requirements (contains a digit). My take would be:

Generate a random password.
If it does not contain a digit (or always):
- Use a random function to get 1 random digit.
- Add it to the random password.
- Randomize the order of the result (so the digit is not necessarily always at the end).

Assuming, that the above script would be named "Get-RandomPassword.ps1", it could look like this:

$pass = .\Get-RandomPassword.ps1
$pass += (0..9 | Get-Random)
$pass = (($pass.GetEnumerator() | Get-Random -Count $pass.Length) -join '')
Write-Output $pass

This can be generalized, to enforce using any character category:

$sets = @('abcdefghijklmnopqrstuvwxyz', 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', '0123456789', '()-_=+[{]};:''",<.>/?`~')
$pass = .\Get-RandomPassword.ps1 -Characters ($sets -join '')
foreach ($set in $sets) {
    $pass += ($set.GetEnumerator() | Get-Random)
}
$pass = (($pass.GetEnumerator() | Get-Random -Count $pass.Length) -join '')
Write-Output $pass

来源：https://stackoverflow.com/questions/37256154/powershell-password-generator-how-to-always-include-number-in-string

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powershell

passwords

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