问题
I have a vector of unique_ptr's and I want to append them to another vector of unique_ptrs. I would normally do a simple insert:
std::vector<std::unique_ptr<foo>> bar;
bar.push_back(std::unique_ptr<foo>(new foo(1)));
std::vector<std::unique_ptr<foo>> baz;
baz.push_back(std::unique_ptr<foo>(new foo(2)));
bar.insert(bar.end(), baz.begin(), baz.end());
However this gives me compile errors similar to this:
/usr/include/c++/4.8/bits/stl_algobase.h:335: error: use of deleted function 'std::unique_ptr<_Tp, _Dp>& std::unique_ptr<_Tp, _Dp>::operator=(const std::unique_ptr<_Tp, _Dp>&) [with _Tp = foo; _Dp = std::default_delete<foo>]'
*__result = *__first;
^
Is there a convenient way to insert or do I have to iterate over baz and push_back on bar? I'm currently using gcc 4.8.1.
Thanks
回答1:
unique_ptr
is not assignable with normal assignment operator (the error says it's deleted). You can only move them:
bar.insert(bar.end(),
std::make_move_iterator(baz.begin()),
std::make_move_iterator(baz.end())
);
Of course, this transfers the ownership of the managed object and original pointers will have nullptr
value.
回答2:
You can't copy them; you'll have to move them.
std::move(baz.begin(), baz.end(), std::back_inserter(bar));
来源:https://stackoverflow.com/questions/21487714/inserting-a-vector-of-unique-ptr-into-another-vector