How to read a file as a byte array in Scala

问题

I can find tons of examples but they seem to either rely mostly on Java libraries or just read characters/lines/etc.

I just want to read in some file and get a byte array with scala libraries - can someone help me with that?

回答1:

Java 7:

import java.nio.file.{Files, Paths}

val byteArray = Files.readAllBytes(Paths.get("/path/to/file"))

I believe this is the simplest way possible. Just leveraging existing tools here. NIO.2 is wonderful.

回答2:

This should work (Scala 2.8):

val bis = new BufferedInputStream(new FileInputStream(fileName))
val bArray = Stream.continually(bis.read).takeWhile(-1 !=).map(_.toByte).toArray

回答3:

val is = new FileInputStream(fileName)
val cnt = is.available
val bytes = Array.ofDim[Byte](cnt)
is.read(bytes)
is.close()

回答4:

The library scala.io.Source is problematic, DON'T USE IT in reading binary files.

The error can be reproduced as instructed here: https://github.com/liufengyun/scala-bug

In the file data.bin, it contains the hexidecimal 0xea, which is 11101010 in binary and should be converted to 234 in decimal.

The main.scala file contain two ways to read the file:

import scala.io._
import java.io._

object Main {
  def main(args: Array[String]) {
    val ss = Source.fromFile("data.bin")
    println("Scala:" + ss.next.toInt)
    ss.close

    val bis = new BufferedInputStream(new FileInputStream("data.bin"))
    println("Java:" + bis.read)
    bis.close
  }
}

When I run scala main.scala, the program outputs follows:

Scala:205
Java:234

The Java library generates correct output, while the Scala library not.

回答5:

You might also consider using scalax.io:

scalax.io.Resource.fromFile(fileName).byteArray

回答6:

You can use the Apache Commons Compress IOUtils

import org.apache.commons.compress.utils.IOUtils

val file = new File("data.bin")
IOUtils.toByteArray(new FileInputStream(file))

来源：https://stackoverflow.com/questions/7598135/how-to-read-a-file-as-a-byte-array-in-scala

标签

scala

bytearray