Customizing layout to sfWidgetFormDoctrineChoice disable checkbox

问题

Good morning,

In Symfony 1.4,
I tried to do what is explained here : Customizing layout to sfWidgetFormDoctrineChoice
But it doesn't work. Instead of adding a thumbnail, I just want to hide the <li> before the input, and in some condition disable/hide the checkbox input but show the label anyway.
When I add the renderer without argument, I get this error :
sfWidgetFormMySelectCheckbox requires the following options: 'choices'.

Here is my formatter code :

class sfWidgetFormMySelectCheckbox extends sfWidgetFormSelectCheckbox
{
  public function configure($options = array(), $arguments = array())
  {
    parent::configure($options, $arguments);
  }

  protected function formatChoices($name, $value, $choices, $attributes)
  {
    .....

      // new
      $inputs[$id] = array(
        'input' => sprintf('| test | %s',
          $this->renderTag('input', array_merge($baseAttributes, $attributes))
        ),
        'label' => $this->renderContentTag('label', self::escapeOnce($option), array('for' => $id)),
      );
    }

    return call_user_func($this->getOption('formatter'), $this, $inputs);
  }
}

And now the form where I call it :

$this->setWidget('aaa', new sfWidgetFormDoctrineChoice(array(
    'model' => 'Aaa',
    'expanded' => true,
    'multiple' => true,
    'add_empty' => false,
    'query' => $query,
    'renderer' => new sfWidgetFormMySelectCheckbox()
  )));

Thanks for your help !

回答1:

According to the docs you have to pass the choices option to the renderer object. Try something like this:

$this->setWidget('aaa', new sfWidgetFormDoctrineChoice(array(
    'model' => 'Aaa',
    'expanded' => true,
    'multiple' => true,
    'add_empty' => false,
    'query' => $query,
)));

$this->widgetSchema['aaa']->setOption('renderer', new sfWidgetFormMySelectCheckbox(array(
    'choices' => new sfCallable(array($this->widgetSchema['aaa'], 'getChoices'))
)));

So basically you want the renderer object get the choices from the parent widget. To do that you have to pass a sfCallable object which takes an array as the first argument in which you pass the instance of your parent widget and the name of the function getChoices.

Remember also that the expanded option is not used when you override the renderer.

来源：https://stackoverflow.com/questions/20118469/customizing-layout-to-sfwidgetformdoctrinechoice-disable-checkbox

标签

php

forms

symfony-1.4