Array.extend(string) adds every character instead of just the string

问题

I am trying to extend an element to a list in Python, however, instead of extending the string in the index 'i' it extends every character of the string in the index 'i'.

For example I have a list called 'strings' with just a string 'string1' and an empty list called 'final_list'.

I want to extend the first element of 'strings' to the 'final_list', so I do final_list.extend(strings[0]). But instead of the 'final_list' to end with a length of 1, corresponding to the string inserted, the list ends up with a length of 7.

If it helps, this is my code:

con = connect()
    i = 0
    new_files = []
    while i < len(files):
        info_file = obter_info(con, files[i])
        if info_file [5] == 0: #file not processed
            new_files.append(files[i])
        i += 1

Does anyone know how can I make this to work?

回答1:

The extend method takes an iterable as an argument, unpacks that iterable and adds each element individually to the list upon which it is called. In your case, you are "extending" a list with a string. A string is an iterable. As such, the string is "unpacked" and each character is added separately:

>>> d = []
>>> d.extend('hello')
>>> print(d)
['h', 'e', 'l', 'l', 'o']

If you simply want to add one element of a list to another list, then use append. Otherwise, surround the string in a list and repeat the extend:

>>> d = []
>>> d.extend(['hello'])
>>> print(d)
['hello']

回答2:

try that one:

final_list.extend([strings[0]])

or:

final_list.append(strings[0])

来源：https://stackoverflow.com/questions/29947007/array-extendstring-adds-every-character-instead-of-just-the-string

标签

python

string

extend