java String's immutability

问题

If I run,

String s1="abc";

then are there any differences between:

String s2=new String(s1);

and

String s2="abc";

Here's what I'm confused about:

The Head First Java says:"If there's already a String in the String pool with the same value, the JVM doesn't create a duplicate, it simply refers your reference variable to the existing entry. " Which at my point of view is that the s1 has already created "abc",s2 just refers to it. Am I right??

回答1:

When you write String s2="abc"; and "abc" is already in the pool, then you won't get a duplicate - you'll get a reference to the existing String.

But if you write new String(something), you get a new String, whether there's a matching String in the pool or not.

回答2:

String Constant Pool comes into picture in this case as shown in below screenshot.

I think it will help you to understand it visually.

String s1="abc"; // s1 will go to String constant pool

String s2=new String(s1); // any object created by "new" keyword will go to Heap

String s2="abc"; // s1 and s2 both will refer to same string in constant pool