How to “extract” Z from subset type {z : Z | z > 0}

问题

If a function take Z as arguments, it should also be possible to take any subset of Z, right? For example, Zmod takes two Z and return Z. Can I improve on this method with subset types without reimplementing it?

I want this:

Definition Z_gt0 := {z | z > 0}.

Definition mymod (n1 n2 : Z_gt0) :=
  Zmod n1 n2.

But Coq complains that n1 is expected to have type Z, of course. How can I make it work with Z_gt0? Coerce?

This question is related to my other one here: Random nat stream and subset types in Coq

Edit: proj1_sig might do the trick, thanks Coq IRC channel!

回答1:

proj1_sig is the usual way to go. Another solution is to pattern match:

match z1 with
   exist _ z hz => ...
end

z will be your projection, and hz will be a proof that z > 0. I usually leave the first parameter anonymous since I know that z : Z.

I recent version of Coq, there is another way to do it, using let (because sig is an inductive with only one constructor):

Definition Zmod_gt0 (z1 z2: Z_gt0) : Z :=
  let (a, _) := z1 in
  let (b, _) := z2 in 
  Zmod a b.

来源：https://stackoverflow.com/questions/26493911/how-to-extract-z-from-subset-type-z-z-z-0