Serialization member by member

问题

I've implemented a template<typename T> Serializer that works on any trivially copyable object of type T, just serializing sizeof(T) bytes.

Then I've implemented a couple of (partial) specializations for other types of interest, like std::vector<T> and std::bacis_string<T>. For other types, I trigger a static_assert(is_trivially_copyable<T>::type, "Unsupported type");.

This is not what I want, because I want to avoid serializing, for example, types with naked pointers, like:

struct C_style_vector{
    size_t size;
    int* ptr;
};

For such kind of types, I assume that the user will define an ad hoc specialization. Conversely, as far as now my Serializer doesn't work with a type like this:

struct Simple_type{
    double d;
    std::vector<int> v;
};

even though every member of Simple_type is serializable by my class.

So, how can I catch types with naked pointers? And how can I tell my serializer to serialize types composed only by serializable members, serializing it member by member?

回答1:

It is not actually simple and cannot be done in C++, without some users additions, since there is no reflection in C++.

You can use something like boost::fusion, but user should use fusion sequences in this case. The best way is that uses boost::serialization I think, user MUST provide serialize/deserialize functions for own types.

Example with fusion.

template<bool Value, typename Next, typename Last>
struct is_serializable_impl
{
private:
   static const bool cvalue = !boost::is_pointer<
   typename boost::remove_reference<
   typename boost::fusion::result_of::deref<Next>::type>::type>::value;
public:
   static const bool value = Value && is_serializable_impl<
   cvalue, typename boost::fusion::result_of::next<Next>::type, Last>::value;
};

template<bool Value, typename Last>
struct is_serializable_impl<Value, Last, Last>
{
   static const bool value = Value;
};

template<typename T>
struct is_serializable :
is_serializable_impl<true, typename boost::fusion::result_of::begin<T>::type,
   typename boost::fusion::result_of::end<T>::type>
{
};

template<typename T, typename = void>
struct serializer;

template<typename T>
struct serializer<T,
typename boost::enable_if<typename 
boost::fusion::traits::is_sequence<T>::type>::type>
{
   static_assert(is_serializable<T>::value, "Not serializable");
};

Live example

来源：https://stackoverflow.com/questions/28500822/serialization-member-by-member

标签

c++

templates

serialization

template-specialization