#Render partial with a model in Layout View

问题

I have a MVC project where I want to render my menu using Model.

I declare the menu contents at the Session_Start event in Global.asax.cs and using break point i knew that it is filling out correctly.

I cannot simply use @Html.Partial("_Menu") inside my _Layout.cshtml

And if I do @Html.Partial("_Menu", Model.Something), I get a

Object reference not set to an instance of an object

error on the Model.

回答1:

First off I would recommend against the session object, but since you're using it then in the Initialize method (override) of a common controller that ALL controllers inherit from you'll grab the menu data from the session, and push it into the viewbag. Then in the _Layout you can retrieve the object from the viewbag (

var navigationItems = ViewBag.NavigationItems as NavigationViewModel;

) as field and use that object anywhere by passing it or a property of it to a partial for rendering (

@Html.Partial("_Navigation", navigationItems) 

).

Hope that helps.

回答2:

You can use Razor - Section for this:

Inside _Layout.cshtml:

<div id=”menu”> 
@RenderSection("Menu", required:false)
</div>

& On the pages (Eg. Index.cshtml) you want Menu:

@section Menu 
{
 @Html.Partial("_Menu", Model.Something)
}

回答3:

Provide more details:

• Why you are using Session_Start?
• How you filling model Model.Something?

The simplest way for creating dynamic menu is @Html.RenderAction.

来源：https://stackoverflow.com/questions/12722320/render-partial-with-a-model-in-layout-view