问题
i have a Django project and right now everything works fine. i have a Django admin site and now, i want that when i add a new record to my model, a function calls simultaneously and a process starts. how i can do this? what is this actions name?
回答1:
- 1 WAY
You can go to your models.py into your app by using django signal you can do this.
from django.db.models.signals import post_save
class Test(models.Model):
# ... fields here
# method for updating
def update_on_test(sender, instance, **kwargs):
# custome operation as you want to perform
# register the signal
post_save.connect(update_on_test, sender=Test)
- 2 WAY
You can ovveride save() method of modeladmin class if you are filling data into table by using django admin.
class TestAdmin( admin.ModelAdmin ):
fields = ['title', 'body' ]
form = TestForm
def save_model(self, request, obj, form, change):
# your login if you want to perform some comutation on save
# it will help you if you need request into your work
obj.save()
来源:https://stackoverflow.com/questions/21852518/call-a-method-in-django-admin-site