问题
Possible Duplicate:
postfix 'd+0' in Fortran real literal expressions
I have this code line in Fortran 90:
OVERN2 = 1.d+0/DBLE(FLOAT(NMODE2))
NMODE2 is an integer, OVERN2 is a REAL*8.
Can you please explain to me what this line does? I don't understand the .d+0/ part?
if you can also translate that to C or any other easier language.
回答1:
1.d+0 is just a double precision literal in scientific notation, i.e. 1.0e0 or just 1.0.
In C it would be:
double overn2 = 1.0 / (double)nmode2;
来源：https://stackoverflow.com/questions/12567575/fortran-basic-help-d-operator