Workaround for Making a unique_ptr to a Forward Declared Type

牧云@^-^@ 提交于 2019-12-11 17:58:54

问题


Given that I have a forward declared type:

class Foo;

I want to make a unique_ptr to this type:

unique_ptr<Foo> pFoo;

This works fine in visual-studio-2017 but I can't make it work in visual-studio-2012.

C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\memory(1150): error C2027: use of undefined type Foo (....\src\STETestbed\STETestbed.cpp)
O:\Engine\stetestbed\include\STETestbed\ComponentDirector.h(26) : see declaration of Foo
C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\memory(1149) : while compiling class template member function void std::default_delete<_Ty>::operator ()(_Ty *) throw() const
with
[
_Ty=Foo
]
C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\memory(1444) : see reference to function template instantiation void std::default_delete<_Ty>::operator ()(_Ty *) throw() const being compiled
with
[
_Ty=Foo
]
C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\type_traits(743) : see reference to class template instantiation std::default_delete<_Ty> being compiled
with
[
_Ty=Foo
]
C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\memory(1281) : see reference to class template instantiation std::is_empty<_Ty> being compiled
with
[
_Ty=std::default_delete
]
O:\Engine\stetestbed\include\STETestbed\ComponentDirector.h(63) : see reference to class template instantiation std::unique_ptr<_Ty> being compiled
with
[
_Ty=Foo
]
C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\memory(1151): error C2338: can't delete an incomplete type (....\src\STETestbed\STETestbed.cpp)
C:\Program Files (x86)\Microsoft Visual Studio 11.0\VC\include\memory(1152): warning C4150: deletion of pointer to incomplete type Foo; no destructor called (....\src\STETestbed\STETestbed.cpp)
O:\Engine\stetestbed\include\STETestbed\ComponentDirector.h(26) : see declaration of Foo

Was there a workaround for that back in the dark ages, or can I just not forward declare?


回答1:


As mentioned by Jarod42 The problem seems to be that the default_deleter implemented by visual-studio-2012 required a complete type on declaration. Latter versions of visual-studio only required the complete type at the point the parenthesis operator is called.

We can work around this by providing a functor which provides a deleter which does not require the complete type on declaration:

template <typename T>
void custom_deleter(T* param) {
    delete param;
}

To use custom_deleter as a template parameter we'll need to make it into a functor otherwise the compiler will error:

error C2207: std::_Unique_ptr_base<_Ty,_Dx,_Empty_deleter>::_Mydel : a member of a class template cannot acquire a function type

So in the header where Foo is forward declared we'll need to define the unique_ptr as:

unique_ptr<Foo, function<void(Foo*)>> pFoo

And in the implementation file where Foo is defined we'll need to assign it as:

pFoo = decltype(pFoo)(new Foo, std::function<void(Foo*)>(custom_deleter<Foo>))


来源:https://stackoverflow.com/questions/57992892/workaround-for-making-a-unique-ptr-to-a-forward-declared-type

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