How to avoid subshell behaviour using while and find? [duplicate]

问题

This question already has answers here:

While-loop subshell dilemma in Bash (4 answers)

Closed 9 months ago.

Because I trapped into this myself, I asked a question and did give also the answer here. If find iterates over what the command did find, this is executed from bash in a subshell. So you can not fill an array with results and use it after your loop.

回答1:

You have to change the syntax from:

i=0
find $cont_dirs_abs -type l -exec test -e {} \; -print0 | while IFS= read -r -d '' lxc_storage_abspath; do
    lxcname=${lxc_storage_abspath##*/}
    ...
    lxcnames[$i]="$lxcname"
    let "i+=1"
done

to

i=0
while IFS= read -r -d '' lxc_storage_abspath; do
    lxcname=${lxc_storage_abspath##*/}
    ...
    lxcnames[$i]="$lxcname"
    let "i+=1"
done < <(find $cont_dirs_abs -type l -exec test -e {} \; -print0)

In my case i can after this loop access the bash array $lxcnames:

i=0
for lxcname in ${lxcnames[*]}; do
    ...
done

Hope that helps anybody.

来源：https://stackoverflow.com/questions/55239979/how-to-avoid-subshell-behaviour-using-while-and-find