问题
having this code
<?php
public function trueOrFalse($handler) {
if (method_exists($handler, 'isTrueOrFalse')) {
$result= $handler::isTrueOrFalse;
return $result;
} else {
return FALSE;
}
}
how would you unit-test it? is there a chance to mock a $handler
? obviously i would need some kind of
<?php
$handlerMock= \Mockery::mock(MyClass::class);
$handlerMock->shouldReceive('method_exists')->andReturn(TRUE);
but it cannot be done
回答1:
Okay In your testCase class you need to use the same namespace of your MyClass
class. The trick is to override built-in functions in your current namespace. So assuming your class looks like the following:
namespace My\Namespace;
class MyClass
{
public function methodExists() {
if (method_exists($this, 'someMethod')) {
return true;
} else {
return false;
}
}
}
Here is how the testCase class should look like:
namespace My\Namespace;//same namespace of the original class being tested
use \Mockery;
// Override method_exists() in current namespace for testing
function method_exists()
{
return ExampleTest::$functions->method_exists();
}
class ExampleTest extends \PHPUnit_Framework_TestCase
{
public static $functions;
public function setUp()
{
self::$functions = Mockery::mock();
}
/**
* A basic functional test example.
*
* @return void
*/
public function testBasicExample()
{
self::$functions->shouldReceive('method_exists')->once()->andReturn(false);
$myClass = new MyClass;
$this->assertEquals($myClass->methodExists(), false);
}
}
It works perfect for me. Hope this helps.
来源:https://stackoverflow.com/questions/37927273/how-to-unit-test-a-php-method-exists