Converting time to a float

问题

I wrote a program to compute the hours I've worked but at the end, it returns the value as a time.

EX: I worked from 11:45 to 4:30. My program returns 4:45 I would like it to return 4.75.

How do I convert this?

I am using the following code:

import datetime as dt

from datetime import timedelta

start =(input("Enter start time: " ))
end =(input("Enter start time: " ))
start_dt = dt.datetime.strptime(start, '%H:%M')
end_dt = dt.datetime.strptime(end, '%H:%M')
time =(end_dt - start_dt)
if time.days < 0:
    time=timedelta(days=0,seconds=time.seconds,microseconds=time.microseconds)
    time= str(time)
    time2=dt.datetime.strptime(time, '%H:%M:%S') 
    off_set=dt.datetime.strptime('12:00:00', '%H:%M:%S')
    time= time2 - off_set 

print (time)

回答1:

If you use a datetime, the hour and minute method should give you what you want

>>>a=datetime.datetime.now().time()
>>>a
datetime.time(21, 17, 35, 562000) 
>>>a.hour+a.minute/60.0
21.283333333333335

If you are using a timedelta (as is the case in your code), you should use :

mytimedelta = atime - anothertime
secs=mytimedelta.seconds #timedelta has everything below the day level stored in seconds
minutes = ((secs/60)%60)/60.0
hours = secs/3600
print hours + minutes

来源：https://stackoverflow.com/questions/47043841/converting-time-to-a-float