Deleting certain rows/columns in a grid Tkinter

问题

If I have several rows and columns with several entry/label widgets in the SAME frame, is it possible to choose just a single one of them and delete it whilst leaving the others alone.

e.g.

class Window():
    def __init__(self):
        self.root = Tk()
        self.win1 = Frame(self.root)
        entry1 = Entry(win1, row=1, column=1)
        entry2 = Entry(win1, row=1, column=2)
        label1 = Label(win1, row=1, column=3)

    def main1(self):
        label2 = Label(win1, row=1, column=4)
        labeln = Label(win1, row=1, column=n)

I would then like to remove from column 3 onwards, where n could be a random number. Is it possible to get grid_forget and insert the number of columns? Is it also possible for the rows as well?

UPDATE: OR is it possible to simply return back to the window created under init and delete those created under main1 (but have been created in the same frame)?

Thank you.

回答1:

Read up on the grid_remove and grid_forget methods; these will alow you to remove existing widgets from view. You can also destroy widgets, causing them to vanish.

It's been a while since I've done this (and don't currently have a computer on which to create an example), but I think the one sticky point may be that you will have to go in and explicitly set the grid row and/or column heights, widths or weights back to zero to reclaim the space. It's quite doable though.

Your other choice is to create all of your widgets via a method or function. You can then pretty easily destroy and recreate all the widgets. This is probably less pleasant for the user since the whole UI will "blink".

回答2:

Here's a csh script to create a dynamic python code for GUI.

What it does?

enter

./dynamic_python -label name,age -frame myframe

and it will create 2 label named name,age , 2 entry box for each label and some other widgets. I know it's not exactly what you need, but consider it at a possible approach to your solution. Ping me if you need more help. Will appreciate other user's feedback :)

CODE for dynamic_python:

#! /bin/csh -f

#echo $argv[1]
#shift
#echo $argv[1]
while ("$#" != 0)
    if("$argv[1]" == "-label") then 
        set label = "$argv[2]"
        shift
        shift
    endif
    if("$argv[1]" == "-frame") then 
        set frame = "$argv[2]"
        shift
        shift
    endif
end
set label = `echo $label | sed 's/,/ /g'`
set lcount = `expr "$#label" + 1`
set lc = 1
#
echo "#! /usr/bin/python" > dy.py
echo "from Tkinter import *" >> dy.py
#
echo "def fun_ok():" >> dy.py
echo "  print 'OK_Accepted'" >> dy.py
set label = `echo $label | sed 's/,/ /g'`
set lcount = `expr "$#label" + 1`
set lc = 1
echo "  list_out = []" >> dy.py
while ($lc != $lcount)
    echo "  print $label[$lc].get()" >> dy.py
    echo "  list_out.append('-$label[$lc]')" >> dy.py
    echo "  list_out.append($label[$lc].get())" >> dy.py
    set lc = `expr "$lc" + 1`
end
echo "  print list_out" >> dy.py
#
echo "$frame = Tk()" >> dy.py
#
set label = `echo $label | sed 's/,/ /g'`
set lcount = `expr "$#label" + 1`
set lc = 1
while ($lc != $lcount)
    echo $lc $label[$lc]
    echo "$label[$lc] = StringVar()" >> dy.py
    echo "Label($frame,text="_$label[$lc]_").grid(row = $lc,column = 1)" | sed 's/_/"/g' >> dy.py
    echo "Entry($frame,textvariable=$label[$lc]).grid(row=$lc,column=2)" >> dy.py
    set lc = `expr "$lc" + 1`
end
echo "Button($frame,text='OK',command=fun_ok).grid(row = $lc,column = 1)" >> dy.py
echo "Button($frame,text='EXIT',command=$frame.quit).grid(row = $lc,column = 2)" >> dy.py
#Button(master, text="OK", command=callback)
#
echo "$frame.mainloop()" >> dy.py
#
chmod 755 *
dy.py

来源：https://stackoverflow.com/questions/11357988/deleting-certain-rows-columns-in-a-grid-tkinter

标签

python

user-interface

tkinter

ttk