问题
Does using a lock have better performance than using a local (single application) semaphore?
I read this blog from msdn : Producer consumer solution on msdn
and I didn't like their solution to the problem because there are always 20 elements left in the queue.
So instead, I thought about using a 'Semaphore' that will be available only in my app (I just won't name it in the constructor), but I don't know how it will effect the app's performance.
Does anyone have an idea if it'll affect the performance? What are the other considerations to use a lock and not 'Semaphore'?
回答1:
Lock(obj) is the same as Monitor.Enter(obj); A lock is basicaly an unary semaphore. If you have a number of instances of the same ressource (N) you use a semaphore with the initialization value N. A lock is mainly used to ensure that a code section is not executed by two threads at the same time.
So a lock can be implemented using a semaphore with initialization value of 1. I guess that Monitor.Enter is more performant here but I have no real information about that. A test will be of help here. Here is a SO thread that handels about performance.
For your problem a blocking queue would be the solution. (producer consumer) I suggest this very good SO thread.
Here is another good source of information about Reusable Parallel Data Structures.
回答2:
TLDR I just ran my own benchmark and in my setup, it seems that lock is running almost twice as fast as SemaphoreSlim(1).
Specs:
- .NET Core
2.1.5 - Windows 10
- 2 physical cores (4 logical) @
2.5 GHz
The test:
I tried running 2, 4 and 6 Tasks in parallel, each of them doing 1M of operations of accessing a lock, doing a trivial operation and releasing it. The code looks as follows:
await semaphoreSlim1.WaitAsync();
// other case: lock(obj) {...}
if(1 + 1 == 2)
{
count++;
}
semaphoreSlim1.Release();
Results
For each case, lock ran almost twice as fast as SemaphoreSlim(1) (e.g. 205ms vs 390ms, using 6 parallel tasks).
Please note, I do not claim that it is any faster on an infinite number of other setups.
回答3:
In general: If your consumer thread manages to process each data item quickly enough, then the kernel-mode transition will incur a (possibly significant) bit of overhead. In that case a user-mode wrapper which spins for a while before waiting on the semaphore will avoid some of that overhead.
A monitor (with mutual exclusion + condition variable) may or may not implement spinning. That MSDN article's implementation didn't, so in this case there's no real difference in performance. Anyway, you're still going to have to lock in order to dequeue items, unless you're using a lock-free queue.
回答4:
The solution in the MSDN article has a bug where you'll miss an event if SetEvent is called twice by the producer in quick succession whilst the consumer is processing the last item it retrieves from the queue.
Have a look at this article for a different implementation using Monitor instead:
http://wekempf.spaces.live.com/blog/cns!D18C3EC06EA971CF!672.entry
回答5:
lock and semaphore slim are entirely different, and I would avoid mixing them. SemaphoreSlim is good if your using async properly.
If your lock surrounds an await call, remember the thread that picks up running after an await will not necessarily the same thread that called it. Its likely to be the same threadcontext but that is a different thing.
Also if your method returns a Task and your method contains a lock, then you will find one of the threadpool threads used to run that task will get blocked until the lock is freed, so you could end up starving any arbitary Task somewhere else in your program of the threads they need to run.
来源：https://stackoverflow.com/questions/3489382/does-using-a-lock-have-better-performance-than-using-a-local-single-application