Brace expansion with a Bash variable - {0..$foo}

问题

WEEKS_TO_SAVE=4
mkdir -p weekly.{0..$WEEKS_TO_SAVE}

gives me a folder called weekly.{0..4}

Is there a secret to curly brace expansion while creating folders I\'m missing?

回答1:

bash does brace expansion before variable expansion, so you get weekly.{0..4}.
Because the result is predictable and safe(Don't trust user input), you can use eval in your case:

$ WEEKS_TO_SAVE=4
$ eval "mkdir -p weekly.{0..$((WEEKS_TO_SAVE))}"

note:

eval is evil
use eval carefully

Here, $((..)) is used to force the variable to be evaluated as an integer expression.

回答2:

Another way of doing it without eval and calling mkdir only once:

WEEKS_TO_SAVE=4
mkdir -p $(seq -f "weekly.%.0f" 0 $WEEKS_TO_SAVE)

回答3:

Curly braces don't support variables in BASH, you can do this:

 for (( c=0; c<=WEEKS_TO_SAVE; c++ ))
 do
    mkdir -p weekly.${c}
 done

回答4:

Brace expansion does not support it. You will have to do it using a loop.

Brace expansion is performed before any other expansions, and any characters special to other expansions are preserved in the result. It is strictly textual. Bash does not apply any syntactic interpretation to the context of the expansion or the text between the braces. To avoid conflicts with parameter expansion, the string ‘${’ is not considered eligible for brace expansion

回答5:

If you happen to have zsh installed on your box, your code as written will work with Z-shell if you use #!/bin/zsh as your interpreter:

Example

$ WEEKS_TO_SAVE=4
$ echo {0..$WEEKS_TO_SAVE}
0 1 2 3 4

来源：https://stackoverflow.com/questions/9337489/brace-expansion-with-a-bash-variable-0-foo

标签

bash

brace-expansion