Escaping ampersands in URLs for HttpClient requests

问题

So I've got some Java code that uses Jakarta HttpClient like this:

URI aURI = new URI( "http://host/index.php?title=" + title + "&action=edit" );
GetMethod aRequest = new GetMethod( aURI.getEscapedPathQuery());

The problem is that if title includes any ampersands (&), they're considered parameter delimiters and the request goes screwy... and if I replace them with the URL-escaped equivalent %26, then this gets double-escaped by getEscapedPathQuery() into %2526.

I'm currently working around this by basically repairing the damage afterward:

URI aURI = new URI( "http://host/index.php?title=" + title.replace("&", "%26") + "&action=edit" );
GetMethod aRequest = new GetMethod( aURI.getEscapedPathQuery().replace("%2526", "%26"));

But there has to be a nicer way to do this, right? Note that the title can contain any number of unpredictable UTF-8 chars etc, so escaping everything else is a requirement.

回答1:

Here you go:

import java.net.URLEncoder;
...
...
URI aURI = new URI( "http://host/index.php?title=" + URLEncoder.encode(title,"UTF-8") + "&action=edit" );
GetMethod aRequest = new GetMethod( aURI.getPathQuery());

Check java.net.URLEncoder for more info.

回答2:

Why are you calling getEscapedPathQuery() if you don't want the escaping? Just decide who's responsibility it is and be consistent.

回答3:

Use the URLEncoder class.

Utility class for HTML form encoding. This class contains static methods for converting a String to the application/x-www-form-urlencoded MIME format. For more information about HTML form encoding, consult the HTML specification.

来源：https://stackoverflow.com/questions/2558111/escaping-ampersands-in-urls-for-httpclient-requests