问题
If you set the Visible property of a Windows Forms control to true, that property still returns false if any of the control's parent windows are hidden. Is there a way to get the true, underlying visibility flag of the control in case the parent window is hidden?
回答1:
Well, the regular implementation does check up the control stack, to ensure that all parents are visible. The only way I know to dodge this is to cheat with reflection, and ask for GetState(2), but that is brittle:
// dodgy; not recommended
Panel query;
Form form = new Form
{
Controls = {
new Panel {
Visible = false,
Controls = {
(query = new Panel {Visible = true})
}
}
}
};
form.Show();
// this is the dodgy bit...
bool visible = (bool)typeof(Control)
.GetMethod("GetState", BindingFlags.Instance | BindingFlags.NonPublic)
.Invoke(query, new object[] { 2 });
回答2:
What I did is temporarily remove the button from its parent controls to check its Visible value and then re-add to the parent controls.
If you need you can track the child index to re-add it at the right index.
回答3:
An option that doesn't rely on reflection would be to recurse through the parents of the control hierarchy looking for one with Visible set to false.
EDIT: See comments for significance of code.
var frm2 = new Form {Text = "Form2"};
var lbl = new Label {Visible = true};
frm2.Controls.Add(lbl);
frm2.Show();
var frm1 = new Form {Text = "Form1"};
var lblVis = new Label { Text = lbl.Visible.ToString(), Left = 10, Top = 10};
lbl.VisibleChanged += (sender, args) => MessageBox.Show("Label Visible changed");
var btnShow = new Button {Text = "Show", Left = 10, Top = lblVis.Bottom + 10};
btnShow.Click += (sender, args) =>
{
frm2.Visible = true;
lblVis.Text = lbl.Visible.ToString();
};
var btnHide = new Button {Text = "Hide", Left = 10, Top = btnShow.Bottom + 10};
btnHide.Click += (sender, args) =>
{
frm2.Visible = false;
lblVis.Text = lbl.Visible.ToString();
};
frm1.Controls.AddRange(new Control[] {lblVis, btnShow, btnHide});
Application.Run(frm1);
回答4:
I have same issue with classes derived from 'ToolStripItem' base class. so I used Available property value to check if item will be displayed or not. problem solved. Sample:
ToolStripItem curItm = menuStrip1.Items[i] as ToolStripItem;
if(curItm is ToolStripItem && curItm.Available) DoAnyThing();
In this sample 'curItm' is an instance of of ToolStripItem derived class.
This problem with Visible/Enabled properties in .Net controls that depend on parent container's Visible/Enabled must be solved by .Net team. I create a costume property named IsVisible/IsEnabled in my own classes that return assigned value for Visible/Enabled properties and not the value that depend on parent container.
来源:https://stackoverflow.com/questions/391888/how-to-get-the-real-value-of-the-visible-property