Jquery fadeOut/fadeIn callback not working

问题

i m building a little script to animate a list. Here is my html structure:

<ul>
   <li class="slider"> Item-1 </li>
   <li class="slider"> Item-2 </li>
   <li class="slider"> Item-3 </li>
   ...
   <li class="slider"> Item-13 </li>
   <li class="slider"> Item-14 </li>
   <li class="slider"> Item-15 </li>
</ul>

<button> Next </button>

I'm displaying only four li at one time, the "next" button fadeOut the displayed four li et fadeIn the next four ones. But the fades are applying both together. I've tried to use callback function on the first fade but i can't make it work.

here is the script:

$('li:gt(3)').css('display', 'none');

//Define the interval of li to display
var start = 0;
var end = 4;

//Get the ul length
var listlength = $("li").length;

$("button").click(function() { 

  // FadeOut the four displayed li 
  $('ul li').slice(start,end).fadeOut(500, function(){

        // Define the next interval of four li to show
        start = start+4;
        end = end+4;

        // Test to detect the end of list and reset next interval
        if( start > listlength ){
          start = 0;
          end = 4;
        }

        //Display the new interval
        $('ul li').slice(start,end).fadeIn(500);
  });    
});

Any clues?

回答1:

The problem is that the .fadeOut() callback is called once per animated element, not once at the end. You could modify your code to keep a counter of how many times it has been called, but far easier - assuming at least jQuery 1.6 - is to use .promise(), which will resolve after all the associated animations complete:

$(document).ready(function() {
  var $lis = $("li.slider"),
    start = 0;

$lis.hide().slice(start, start+4).show();

$("button").click(function() {
    $lis.slice(start, start+4)
        .fadeOut(500)
        .promise()
        .done(function() {
            start += 4;
            if (start > $lis.length)
               start = 0;
            $lis.slice(start, start+4).fadeIn();
    });
});    
});

Demo: http://jsfiddle.net/w7Yuk

I made a couple of other changes to your code, e.g., caching the jQuery object with the li elements, and removing the "end" variable.

回答2:

I created a nice little jsFiddle demo that modifies what you had and gets you a nice smooth transition:

HTML:

Give button an id of "next" so that you can target it specifically, in case there are other buttons on page.

<ul>
   <li class="slider"> Item-1 </li>
   <li class="slider"> Item-2 </li>
   <li class="slider"> Item-3 </li>
   <li class="slider"> Item-4 </li>
   <li class="slider"> Item-5 </li>
   <li class="slider"> Item-6 </li>
   <li class="slider"> Item-7 </li>
   <li class="slider"> Item-8 </li>
   <li class="slider"> Item-9 </li>
   <li class="slider"> Item-10 </li>
   <li class="slider"> Item-11 </li>
   <li class="slider"> Item-12 </li>
   <li class="slider"> Item-13 </li>
   <li class="slider"> Item-14 </li>
   <li class="slider"> Item-15 </li>
   <li class="slider"> Item-16 </li>
</ul>

<button id="next"> Next </button>

CSS:

Start both off with display none so we can fade them in nicely on load.

.slider { display: none; }
#next { display: none; }

jQuery:

I like to cache elements, so I started off by doing that. I then fade in both the first 4 LI elements and the next button. I use the recommended handler of .on() to bind the click event of the next button. After we set start and end we call .fadeOut() on the next button and the current 4 LI elements. Now, the reason your callback is screwy is due to the fact that their is a callback for every element in your selector ( so 4 times ). Instead, we need to use .promise() to wait for all of them to complete as a whole and then we can call the .fadeIn() method on both the next button and the next 4 LI elements. Just a side note, I use .stop(true,true) to eliminate any animation queuing that there might be.

var $list = $("ul li");
var $next = $("#next");
var start = 0;
var end = 4;

$next.fadeIn(500);
$list.slice(start,end).fadeIn(500);

$next.on("click", function() {

  start += 4;
  end += 4;

  if( start >= $list.length ){
    start = 0;
    end = 4;
  }

  $next.stop(true,true).fadeOut(500);
  $list.stop(true,true).fadeOut(500);

  $list.promise().done(function() {
    $list.slice(start,end).stop(true,true).fadeIn(500);
    $next.stop(true,true).fadeIn(500);
  });

});

来源：https://stackoverflow.com/questions/10183591/jquery-fadeout-fadein-callback-not-working