How to escape parenthesis in grep

问题

I want to grep for a function call 'init()' in all JavaScript files in a directory. How do I do this using grep?

Particularly, how do I escape parenthesis, ()?

回答1:

It depends. If you use regular grep, you don't escape:

echo '(foo)'|grep '(fo*)'

You actually have to escape if you want to use the parentheses as grouping.

If you use extended regular expressions, you do escape:

echo '(foo)'|grep -E '\(fo*\)'

回答2:

If you want to search for exactly the string "init()" then use fgrep "init()" or grep -F "init()".

Both of these will do fixed string matching, i.e. will treat the pattern as a plain string to search for and not as a regex. I believe it is also faster than doing a regex search.

回答3:

$ echo "init()" | grep -Erin 'init\([^)]*\)'
1:init()

$ echo "init(test)" | grep -Erin 'init\([^)]*\)'
1:init(test)

$ echo "initwhat" | grep -Erin 'init\([^)]*\)'

回答4:

Move to your root directory (if you are aware where the JavaScript files are). Then do the following.

grep 'init()' *.js

来源：https://stackoverflow.com/questions/3673594/how-to-escape-parenthesis-in-grep