问题
I created a template driven form in angular 5
I want to disable the whole form at first, and also want the form to be enabled once some button is clicked, Hence I added a disabled property in the form tag and made its value as false as shown below , (this didn't work though):
<form #formName = "ngForm" [disabled]="true">
</form>
As the above disabled property didn't work, I changed the disabled property as
[attr.disabled] = true
This also didn't work
Now as I have the form element's reference which is #formName
, I used it in the TS file and tried to change the disabled property value inside the reference object
Here's what I have done :
@ViewChild('formName') formName;
this.formName.disabled = true;
which also didn't work and I got an error message saying disabled cannot be changed as it is only a getter
How should I disable the whole form by default in angular on template driven forms ?
Thanks in advance :)
回答1:
As mentioned in the comment you can wrap the form inside a fieldset
tag and achieve this as below,
<form #formName = "ngForm" >
<fieldset [disabled]="disabledValue">
</form>
and you can change it in the code by having a local variable and toggle between the disabled/enabled state as
this.disabledValue = true;
来源:https://stackoverflow.com/questions/49533780/how-to-disable-all-the-fields-in-a-template-driven-form-in-angular