Linux's thread local storage implementation

ε祈祈猫儿з 提交于 2019-11-27 00:28:18

问题


__thread Foo foo;

How is "foo" actually resolved? Does the compiler silently replace every instance of "foo" with a function call? Is "foo" stored somewhere relative to the bottom of the stack, and the compiler stores this as "hey, for each thread, have this space near the bottom of the stack, and foo is stored as 'offset x from bottom of stack'"?


回答1:


It's a little complicated (this document explains it in great detail), but it's basically neither. Instead the compiler puts a special .tdata section in the executable, which contains all the thread-local variables. At runtime, a new data section for each thread is created with a copy of the data in the (read-only) .tdata section, and when threads are switched at runtime, the section is also switched automatically.

The end result is that __thread variables are just as fast as regular variables, and they don't take up extra stack space, either.



来源:https://stackoverflow.com/questions/2459692/linuxs-thread-local-storage-implementation

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!