问题
Following the pointers from this question.
I'd like to calculate the cumulative time for all the Cats, by considering their respective last toggle status.
EDIT:
I'd also want to check if the FIRST Toggle status of a Cat is Off and if it is so, for that specific cat, the time from midnight 00:00:00 till this first FIRST Off time should be added to its total conditional cumulative ontime.
Sample data:
       Time Cat Toggle
1  05:12:09  36 On
2  05:12:12 26R Off # First Toggle of this Cat happens to be Off, Condition met
3  05:12:15 26R On
4  05:12:16 26R Off
5  05:12:18  99 Off # Condition met
6  05:12:18  99 On
7  05:12:24  36 Off
8  05:12:26  36 On
9  05:12:29  80 Off # Condition met
10 05:12:30  99 Off
11 05:12:31  95 Off # Condition met
12 05:12:32  36 Off
Desired sample output:
  Cat Time(Secs)
1 36  21
2 26R 18733 # (=1+18732), 18732 secs to be added = total Sec from midnight till 05:12:12
3 99  18750 # (=12+18738), 18738 secs to be added = total Sec from midnight till 05:12:18
4 ..  ..
Any sort of help is appreciated.
回答1:
A possible solution using data.table:
# load the 'data.table'-package, convert 'df' to a 'data.table'
# and 'Time'-column to a time-format
library(data.table)
setDT(df)[, Time := as.ITime(Time)]
# calculate the time-difference
df[, .(time.diff = sum((shift(Time, type = 'lead') - Time) * (Toggle == 'On'), na.rm = TRUE))
   , by = Cat]
which gives:
Cat time.diff 1: 36 21 2: 26R 1 3: 99 12 4: 80 0 5: 95 0
In respons to your question in the comments, you could do:
# create a new data.table with midnigth times for the categories where
# the first 'Toggle' is on "Off"
df0 <- df[, .I[first(Toggle) == "Off"], by = Cat
          ][, .(Time = as.ITime("00:00:00"), Cat = unique(Cat), Toggle = "On")]
# bind that to the original data.table; order on 'Cat' and 'Time'
# and then do the same calculation
rbind(df, df0)[order(Cat, Time)
               ][, .(time.diff = sum((shift(Time, type = 'lead') - Time) * (Toggle == 'On'), na.rm = TRUE))
                                 , by = Cat]
which gives:
Cat time.diff 1: 26R 18733 2: 36 21 3: 80 18749 4: 95 18751 5: 99 18750
An alternative with base R (only original question):
df$Time <- as.POSIXct(df$Time, format = "%H:%M:%S")
stack(sapply(split(df, df$Cat),
             function(x) sum(diff(x[["Time"]]) * (head(x[["Toggle"]],-1) == 'On'))))
which gives:
values ind 1 1 26R 2 21 36 3 0 80 4 0 95 5 12 99
Or with the tidyverse (only original question):
library(dplyr)
library(lubridate)
df %>% 
  mutate(Time = lubridate::hms(Time)) %>% 
  group_by(Cat) %>% 
  summarise(time.diff = sum(diff(Time) * (head(Toggle, -1) == 'On'),
                            na.rm = TRUE))
    回答2:
using base R:
df$Time=as.POSIXct(df$Time,,"%H:%M:%S")
stack(by(df,df$Cat,function(x)sum(c(0,diff(x$Time))*(x$Toggle=="Off"))))
  values ind
1      1 26R
2     21  36
3      0  80
4      0  95
5     12  99
    回答3:
One can use as.difftime function to convert time from H:M:S format to seconds. Then for each On statue find the lead record in order to calculate interval of time lapsed from On. 
library(dplyr)
# Convert Time in seconds.
df %>% mutate(Time = as.difftime(Time, units = "secs")) %>%
  group_by(Cat) %>%
  mutate(TimeInterVal = ifelse(Toggle == "On", (lead(Time) - Time), 0)) %>%
  summarise(TimeInterVal = sum(TimeInterVal))
# # A tibble: 5 x 2
#   Cat   TimeInterVal
#   <chr>        <dbl>
# 1 26R           1.00
# 2 36           21.0 
# 3 80            0   
# 4 95            0   
# 5 99           12.0 
Note: On can consider arranging data on Time ensure rows are ordered on time. 
Data:
df <- read.table(text ="
Time Cat Toggle
1  05:12:09  36 On
2  05:12:12 26R Off
3  05:12:15 26R On
4  05:12:16 26R Off
5  05:12:18  99 Off
6  05:12:18  99 On
7  05:12:24  36 Off
8  05:12:26  36 On
9  05:12:29  80 Off
10 05:12:30  99 Off
11 05:12:31  95 Off
12 05:12:32  36 Off",
header = TRUE, stringsAsFactors = FALSE)
    来源:https://stackoverflow.com/questions/51118608/calculating-conditional-cumulative-time