问题
The below Stream expression works perfectly fine:
Stream<String> s = Stream.of("yellow","blue", "white");
s.sorted(Comparator.reverseOrder())
.forEach(System.out::print);` //yellowwhiteblue
Why doesn't the equivalent one with method references compile?
s.sorted(Comparator::reverseOrder).forEach(System.out::print);
The type Comparator does not define reverseOrder(String, String) that is applicable here
回答1:
A method reference is telling Java "treat this method as the implementation of a single-method interface"--that is, the method reference should have the signature int foo(String,String) and thus implement Comparator<String>.
Comparator.reverseOrder() doesn't--it returns a Comparator instance. Since sorted is looking for a Comparator, it can take the result of the method call, but it can't use that method as the interface implementation.
回答2:
The line of code with method reference s.sorted(Comparator::reverseOrder) is telling Java that there is a static method with the signature of a trivial method comparator, it means with two parameters.
The class Comparator has only the static method reverseOrder without parameters, that's the reason of the compiling error.
来源：https://stackoverflow.com/questions/43036611/why-doesnt-sortedcomparatorreverseorder-work