How to correctly close a socket and then reopen it?

问题

I'm developing a game for a class that I am in, and it is about 99% done. However, I realized there is a problem: If the server and client disconnect, and the client attempts to reconnect (and the server is back up and running fine), the client is not making a new connection.

The server and client are both multi-threaded. If I send the client a Kick message, what happens is the client will close its socket. If I reconnect, I get a SocketException: socket closed even though whenever connect is pressed, a new Client is constructed, which is basically just a class that creates a socket and connects to the server with a get/send thread.

Do you think there is anything I am doing illogically? It is like it is attempting to use the old Socket and Client that were constructed, but if I do some println calls, I can see that it does construct a new one and they are in different memory locations.

Thanks!

回答1:

After closing a socket, you cannot reuse it to share other data between Server and Client classes. From the Java Socket API, about close() method's description:

Any thread currently blocked in an I/O operation upon this socket will throw a SocketException.

Once a socket has been closed, it is not available for further networking use (i.e. can't be reconnected or rebound). A new socket needs to be created.

Closing this socket will also close the socket's InputStream and OutputStream.

If this socket has an associated channel then the channel is closed as well.

Then, it isn't possible to close a socket and reopen it. That's the reason, I think, of the exception being thrown.

回答2:

It can be easy! I made this program (server side):

import java.net.ServerSocket;
import java.net.Socket;
import java.io.DataInputStream;
import java.io.DataOutputStream;

public class Host{
    public static void main(String[] args) throws Exception{
        while(true){
            ServerSocket ss = new ServerSocket(1300);
            Socket s = ss.accept();
            DataInputStream din = new DataInputStream(s.getInputStream());
            String msgin = din.readUTF();
            System.out.println(msgin);
            ss.close();
            s.close();
            din.close();
        }
    }
}

Client side:

import java.net.Socket;
import java.io.DataInputStream;
import java.io.DataOutputStream;

public class Client{
    public static void main(String[] args) throws Exception{
        while(true){
            Socket s = new Socket("localhost", 1300);
            DataOutputStream dout = new DataOutputStream(s.getOutputStream());
            dout.writeUTF("hello");
            s.close();
            dout.close();
        }
    }
}

It works, beacuse you can declare tons of Sockets with the same ServerSocket, so for example this works too:

ServerSocket ss = new ServerSocket(1300);
Socket a = ss.accept();
Socket b = ss.accept();
Socket c = ss.accept();

and you have 3 Sockets... Remember: java waits for a client to connect when you declare a Socket! Code:

Client:

import java.net.Socket;

public class client {
    public static void main(String[] args) throws Exception{
        Socket a = new Socket("localhost", 1300);
        Thread.sleep(3000);
        Socket b = new Socket("localhost", 1300);
        Thread.sleep(3000);
        Socket c = new Socket("localhost", 1300);
        Thread.sleep(3000);
        a.close();
        b.close();
        c.close();
    }
}

Server:

import java.net.ServerSocket;
import java.net.Socket;

public class server {
    public static void main(String[] args) throws Exception{
        ServerSocket ss = new ServerSocket(1300);
        System.err.println("Listening...");
        Socket a = ss.accept();
        System.err.println("1");
        Socket b = ss.accept();
        System.err.println("2");
        Socket c = ss.accept();
        System.err.println("3");
    }
}

来源：https://stackoverflow.com/questions/8465394/how-to-correctly-close-a-socket-and-then-reopen-it

标签

java

sockets

client

socketexception