Get number before selected word form string using preg_match function in php

Question

I am trying to get the mm and inches values from the following string using preg_match.

$string = "Gold 5.0mm Rolo Chain 18" In";

How can I do this?

Answer 1

Regex: ([\d\.]+)(?:mm|\")

([\d\.]+)(?:mm|\") This will match digits , . before mm and ".

PHP code demo

<?php

ini_set('display_errors', 1);
$string='Gold 5.0mm Rolo Chain 18" In';
preg_match_all("/([\d\.]+)(?:mm|\")/", $string,$matches);
print_r($matches);// its 1 index will return your desired result

Or:

Regex: /[\d\.]+(?=mm|\")/

[\d\.]+(?=mm|\") match digits , . and positively look ahead for mm and "

PHP code demo

<?php
ini_set('display_errors', 1);
$string='Gold 5.0mm Rolo Chain 18" In';
preg_match_all("/[\d\.]+(?=mm|\")/", $string,$matches);
print_r($matches);

Answer 2

want to mm number and In number from string.

I guess you can use:

preg_match_all('/[\d.]+/si', $s, $m);
print_r($m[0]);

Output:

Array
(
    [0] => 5.0
    [1] => 18
)

Answer 3

$string = 'Gold 5.0mm Rolo Chain 18" In"';

preg_match('/([\d\.]+)[m]{2}[A-z\ ]+([\d]+)[A-z\"\ ]+/',$string,$matches);

/**
* $match[1] - 5.0
* $match[2] - 18
*/