ECDF in python without step function?

こ雲淡風輕ζ 提交于 2019-12-06 08:47:30

If you just want to change the plot, then you could let matplotlib interpolate between the observed values.

>>> xx = np.random.randn(nobs)
>>> ecdf = sm.distributions.ECDF(xx)
>>> plt.plot(ecdf.x, ecdf.y)
[<matplotlib.lines.Line2D object at 0x07A872D0>]
>>> plt.show()

or sort original data and plot

>>> xx.sort()
>>> plt.plot(xx, ecdf(xx))
[<matplotlib.lines.Line2D object at 0x07A87090>]
>>> plt.show()

which is the same as plotting it directly

>>> a=0; plt.plot(xx, np.arange(1.,nobs+1)/(nobs+a))
[<matplotlib.lines.Line2D object at 0x07A87D30>]
>>> plt.show()

Note: depending on how you want the ecdf to behave at the boundaries and how it will be centered, there are different normalizations for "plotting positions" that are in common use, like the parameter a that I added as example a=1 is a common choice.

As alternative to using the empirical cdf, you could also use an interpolated or smoothed ecdf or histogram, or a kernel density estimate.

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